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3 years ago

The nucleus of most atoms is composed of which of the following sub-atomic particles? (A) tightly packed neutrons

Physics

1 answer:

solmaris [256]3 years ago

4 0

Answer:

(B) tightly packed protons and neutrons

Explanation:

Nucleus of any atom is the dense central part of any atom.
It consists of two sub-atomic particle namely proton and neutron.
These sub-atomic parts are tightly packed in nucleus which makes the nucleus dense .
This dense nucleus is responsible for most of the mass of atom.
The atomic mass for any atom is decided by sum of the mass of proton and neutron

Thus, correct answer is

(B) tightly packed protons and neutrons

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B. Jerome plays middle linebacker for South's varsity football team. In a game against

weqwewe [10]

Answer:

Option D

670 Kg.m/s

Explanation:

Initial momentum is given by mv=82*5.6=459.2 Kg.m/s (taking eastward as positive)

Final momentum is also mv but v being westward direction, we take it negative

Final momentum=82*-2.5= -205 Kg.m/s

Change in momentum=Final momentum-Initial momentum=-205-459.2=-664.2 Kg.m/s

Impulse=change in momentum=664.2 Kg.m/s rounded off as 670 Kg.m/s

4 0

3 years ago

3. When two things are the same temperature:

JulijaS [17]

The answer is definitely C.) their molecules move at the same average speed

3 0

3 years ago

You are designing an elevator for a hospital. The force exerted on a passenger by the floor of the elevator is not to exceed 1.7

HACTEHA [7]

Answer:

5.62 m/s

Explanation:

Newton's law of motion can be used to determine the maximum speed of the elevator. In the question, we are given:

Force exerted by the elevator (R) = 1.7 times the weight of the passenger (m*g)

Thus: R = 1.7*m*g

Distance (s) = 2.3 m

Newton's second law of motion: R - m*g = m*a

1.7*m*g - m*g = m*a

a = 0.7*m*g/m = 0.7*g = 0.7*9.8 = 6.86 m/s²

To determine the maximum speed:

$v^{2} _{f} = v^{2} _{i} + 2as$ $= 0 + 2(6.86)(2.3) = 31.556$

$v_{f} = \sqrt{31.556} = 5.62 m/s$

Therefore, the elevator maximum speed is equivalent to 5.62 m/s.

8 0

3 years ago

A bungee cord is 30m long and when stretched a distance x itexerts a restoring force of magnitude kx. Your father-in-law (mass95

madam [21]

Answer:

The distance the bungee cord that would be stretched 0.602 m, should be selected when pulled by a force of 380 N.

Explanation:

As from the given data

the length of the rope is given as l=30 m

the stretched length is given as l'=41m

the stretched length required is give as y=l'-l=41-30=11m

the mass is m=95 kg

the force is F=380 N

the gravitational acceleration is g=9.8 m/s2

The equation of k is given by equating the energy at the equilibrium point which is given as

$U_{potential}=U_{elastic}\\mgh=\dfrac{1}{2} k y^2\\k=\dfrac{2mgh}{y^2}$

Here

m=95 kg, g=9.8 m/s2, h=41 m, y=11 m so

$k=\dfrac{2mgh}{y^2}\\k=\dfrac{2\times 95\times 9.8\times 41}{11^2}\\k=630.92 N/m$

Now the force is

$F=kx\\$ or

$x=\dfrac{F}{k}\\$

So here F=380 N, k=630.92 N/m

$x=\dfrac{F}{k}\\x=\dfrac{380}{630.92}\\x=0.602 m$

So the distance is 0.602 m

6 0

3 years ago

A traffic accident detective measures the skid marks left by a car, 825kg. He determines that the distance between the point tha

deff fn [24]

Doing a force balance on the car:
ma = Fr
ma = μmg
a = μg
a = 0.3(9.81)
a = 29.43 m/s2

Using the formula:
2ax = v2
2(29.43)(34) = v2
v = 44.74 m/s = 161.05 km/h

The car was going 44.74 m/s or 161.05 kph when the brakes were applied.

7 0

3 years ago