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2 years ago

What is the complete ground state electron configuration for the zinc atom?

Chemistry

2 answers:

ahrayia [7]2 years ago

8 0

Answer:

2,8,8,8,4

zinc

guapka [62]2 years ago

3 0

Agreed with guy above thanks

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The average American is looking at their phone for 6.25 hours a day. How many hours will the average American spend on their pho

julia-pushkina [17]

Answer:

177253.125hrs

Explanation:

Given parameters:

Number of hours spend per day on phone = 6.25hrs

Unknown:

Average hours pend by an average American if they lived for 77.7yrs

Solution:

Let us find the number of hours an average American spends on their phone per year;

there are 365days in a year

Number of hours = 365 x 6.25 = 2,281.25hrs

Now, if they lived for 77.7yrs;

They will spend = 77.7 x 2,281.25 = 177253.125hrs

8 0

2 years ago

Hey! need help with chem, multiple choice questions.

ladessa [460]

1. 6 carbon atoms and triple bonding between carbons 2 and 3
2. i think it’s 3 but i may be wrong

7 0

2 years ago

How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g

SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

Lead = 1.30 g

So,

ppm of Lead = $\frac{Lead}{Water} \times 10^6$ = $\frac{1.30}{250} \times 10^6$ = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0

2 years ago

what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?

Law Incorporation [45]

A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is ( $M1V1 = M2V2$ ).

Utilize the titration method of $M1V1 = M2V2$ in view that we're given the concentrations of every compound and the quantity of $KOH$ . Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

M1 = initial mass
V1= initial volume
M2 = final mass
V2= final volume

$(M1V1 = M2V2)$
(0.138)(V1) = (0.205)x(26.0)
V2=(0.205)x(26.0)\ 0.138
V2 = 47.10 M/L
The final value of Volume needed for neutralization of nitric acid solution is V2 = 47.10 M/L