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Umnica [9.8K]
3 years ago
5

Please answer fast please ​

Chemistry
1 answer:
slega [8]3 years ago
4 0

I don't know which one I should answer

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Identify each type of bond:
zloy xaker [14]

Answer:

The type of bond between the Oxygen atom and the hydrogen is Covalent

this is because the 2 electrons are being shared by both hydrogen and oxygen

The type of bond this molecule makes as a whole is called a Hydrogen Bond

A hydrogen bond is formed because of the partial +ve and -ve charge in a molecule

The cause of the partial +ve and -ve charge is the comparatively high electronegativity of oxygen which makes the electron get attracted towards the oxygen atom while the hydrogens try to maintain the maximum distance from the lone pairs due to repulsion

Hope it helped

Kindly Mark Brainliest

6 0
3 years ago
Which type of reaction does this diagram represent?
Citrus2011 [14]

Answer:

Nuclear fission

Explanation:

Because the little particles are being spread out and the two elements are broken apart

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2 years ago
The nucleus of an atom consists of
Ksenya-84 [330]

Answer:

The nucleus of an atom consists of Protons and Neutrons.-A.

5 0
3 years ago
Read 2 more answers
Rank the members of each set of compounds in order of decreasing ionic character of their bonds. Use partial charges to indicate
Firdavs [7]

Answer:

Ionic character

A.  PF₃ > PBr₃ > PCl₃

B. BF₃ > CF₄ > NF₃

C. TeF₄ > BrF₃ > SeF₄

Explanation:

The most electronegative element is fluorine, followed chlorine, phosphorous nitrogen etc.

  • Atoms with high electronegativity tend to form negative ions.
  • Ionic compounds formed between elements with high electronegativity difference.
  • % ionic character is directly proportional to electronegativity difference.
  • According to Pauling Scale E.n for F(4.0), O(3.5), N(3.0), C(2.5), B(2.0), P(2.19), Se(2.55) , Te (2.1), Cl(3.16) and Br(2.96)
  • ΔE.N (Electronegativity difference) between( P and F = 4 - 2.19 = 1.81), (P and Br = 2.96 - 2.19 = 0.77) , (P and Cl = 3.16 - 2.96 = 0.2 )
  • ΔE.N (Electronegativity difference) between( N and F = 4 - 3 = 1), (B and F = 4 - 2 = 2) , (C and F = 4 - 2.5 = 1.5 )
  • ΔE.N (Electronegativity difference) between( Se and F = 4 - 2.55 = 1.45), (F and Te = 4 - 2.1 = 1.9) , (F and Br = 4 - 2.19 = 1.81 )

6 0
3 years ago
In a metabolic pathway, succinate dehydrogenase catalyzes the conversion of succinate to fumarate. the reaction is inhibited by
Pani-rosa [81]

Competitive inhibitor

7 0
3 years ago
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