Answer:
1.35 g
Explanation:
Data Given:
mass of Potassium Permagnate (KMnO₄) = 3.34 g
Mass of Oxygen: ?
Solution:
First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)
So,
Molar Mass of KMnO₄ = 39 + 55 + 4(16)
Molar Mass of KMnO₄ = 158 g/mol
Calculate the mole percent composition of Oxygen in Potassium Permagnate (KMnO₄).
Mass contributed by Oxygen (O) = 4 (16) = 64 g
Since the percentage of compound is 100
So,
Percent of Oxygen (O) = 64 / 158 x 100
Percent of Oxygen (O) = 40.5 %
It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.
So,
for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be
mass of Oxygen (O) = 0.405 x 3.34 g
mass of Oxygen (O) = 1.35 g
Answer:3.7427017316233497
Explanation:
I think it might be about 65.31 N on the moon...I've never done this before but what I did was divide 400N by 9.8 to get their mass then multiply the MASS by 1.6 to get the WEIGHT on the moon
<h3>
Answer:</h3>
7.502 kilo calories
<h3>
Explanation:</h3>
<u>We are given;</u>
- Quantity of heat, Q as 31.39 kJ
We are required to convert it to kilo calories
First, we convert it to Joules
1 kJ = 1000 J
Therefore;
31.39 kJ will be equivalent to 31390 Joules
Second we convert Joules to calories using a suitable conversion factor
The suitable conversion factor is 4.184 J/Cal
Thus;
31390 Joules will be equivalent to;
= 31390 J ÷ 4.184 J/Cal
= 7502.39 Cal
Third, we convert calories to kilo calories
1 kCal = 1000 cal
Therefore;
7502. 39 Cal will be equivalent to;
= 7502.39 ÷ 1000
= 7.50239
=7.502 kilo calories
Hence, 31.39 kJ will correspond to 7.502 kilo calories
Answer: a disturbance that transfers energy.
Explanation: