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SpyIntel [72]
3 years ago
15

Benjamina started her walk from the front door of her ground floor apartment.She walked 6 meters to the corner of the building a

nd then turned the corner and walked 10 meters to her friends apartment.Identify the difference between the distance she walked and her displacement.
Chemistry
1 answer:
Nookie1986 [14]3 years ago
8 0

Answer:

See explanation

Explanation:

The major difference between distance and displacement is that distance is a scalar quantity while displacement is a vector quantity. Scalar quantities have magnitude without direction while vector quantities have both magnitude and direction.

The distance covered by Benjamina in both cases just refer to the difference in her position at each time without reference to the direction in which she changed her position.

Her displacement will clearly mention the direction in which she moved both when she walked to the front door of her apartment and when she walked to a friend's apartment.

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Answer:

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Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\

Then, we add the half reactions:

2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0

Thereby, we can see d. 8 moles of H2O on the product side.

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