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m_a_m_a [10]
3 years ago
6

Determine if the two lines are parallel, perpendicular, or neither. Show the work used to get your answer

Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:

Perpendicular

Step-by-step explanation:

[1] We need to find the slopes of both lines! First, we will put them into standard form and then solve.

Standard form: y=mx+b

(1) 10x + 2y = 4

(subtract 10x from both sides)

2y = -10x + 4

(divide both sides by 2)

y = 5x+2

The slope is 5

(2) 5y - x = -5

(add x to both sides)

5y = x - 5

(divide both sides by 5)

y = \frac{1}{5} x - 1

The slope is one-fifth

[2] Then, we need to determine if they are parallel, perpendicluar, or neither.

- If they are parallel they will have the same slope

- If they are perpendicular they will have exact opposite slopes

() Line 1 has a slope of 5 and line two has a slope of one-fifth. These are exact opposites so the lines are perpendicular.

(I hope this is correct and helped, have a nice day!)

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Find the equation of the line passing through the points (3,7) and (-2,5)
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Answer:

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Step-by-step explanation:

Greetings !

first \: find \: the \: slope \: m \\ m =  \frac{(Y₂-Y₁)}{(X₂-X₁)} ..substitute \: vlues \\ m =  \frac{(5 - 7)}{( - 2 - 3)}  =  \frac{ - 2}{ - 5}  =  \frac{2}{5}  \\ y = mx + b \: to \: find \: equation \: of \: aline \\ between \: two \: poins and \: use \:  \\ one \: of \: the \: two \: points \: lets \: take( - 2.5) \\ y = mx + b \\ 5 =  \frac{ - 2}{5} ( - 2) + b \\ 5 =  \frac{ - 4}{5}  + b \\ 5 +  { - 4}^{5}  = b \\  \frac{25 + 4}{5}  = b \\ b =  \frac{29}{5}  \\ finally \: equation \: of \: the \: line \: will \: be \\ y =  \frac{2}{5} x +  \frac{29}{5}

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