A solution with a pH of 6.52 has a hydronium ion concentration of 3.02x10-7 mol/L and a hydroxide ion concentration of 3.31x10-8 mol/L.
The hydronium ion concentration of a solution can be calculated from pH by using
. For a pH of 6.52, hydronium ion concentration is 3.02x10-7 mol/L.
The concentration of hydroxide ions can be determined by identifying the value of pOH. The sum of pOH and pH is equal to 14, which is based on the negative logarithm of the ion-product constant of water. At a pH of 6.52, pOH is equal to 7.48.
The relationship between pOH and hydroxide ion concentration is the same as the relationship between pH and hydronium ion concentration. With this, the hydroxide ion concentration at pOH of 7.48 is
or 3.31x10-8 mol/L.
For more information regarding pH and pOH, please refer to the link brainly.com/question/13557815.
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Answer:</h3>
298.15 K
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Explanation:</h3>
W e are supposed to calculate the Value of K at 25°C
Assuming the value of K represent K, the question wants us to convert degree Celsius to Kelvin.
- To convert degrees Celsius to kelvin scale, we use the relationship;
- Kelvin (K) = Degrees Celsius + 273.15 ; 273.5 is a constant
- That is, to convert temperature from °C to Kelvin we add a constant of 273.15 to the °C given.
In this case;
Temperature is 273.15 °c
Thus, to Kelvin scale temperature will be;
= 25°C + 273.15
= 298.15 K
Therefore, the value of K, at 25°C is 298.15 K
One needs to rank from the most conductive to the least conductive among the formulas that are given in the question. The ranking will be as given below.
<span>1. AlCl3
2. KBr
3. C3H7OOH
4. C6H12O6
</span>
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.
Answer:
C
Explanation:
Think about it. If you accelerate, you go faster. This means you change speed.
The heat required to raise the temperature of the cup from 25 c to 50 c is calculated as follows
Q (heat) = c x delta T
c = specific heat capacity = 0. 820 j/c
delta T = change in temperature ( 50 c- 25 c = 25c
= 0.820 j /c x 25 c = 20.5 j