<span>Let's </span>assume that the gas is an ideal gas. Then we can use ideal gas equation,<span>
PV = nRT<span>
</span>Where,
P = Pressure of the gas (Pa)
V = volume of the gas (m³)
n = number of moles (mol)
R = Universal gas constant (8.314 J mol</span>⁻¹ K⁻¹)<span>
T = temperature in Kelvin (K)
<span>
The given data for the </span></span>gas is,<span>
P = ?
V = 9.5 L = 9.5 x 10</span>⁻³ m³<span>
T = (273 + 20) K = 293 K
R = 8.314 J mol</span>⁻¹ K⁻¹<span>
n = 1.2 mol
by applying the formula,
P x </span>9.5 x 10⁻³ m³ = 1.2 mol x 8.314 J mol⁻¹ K⁻¹ x 293 K
<span> P = 307705.5 Pa
P =3.08 x 10</span>⁵ Pa
<span>
Hence, the pressure of the gas is </span>3.08 x 10⁵ Pa.<span>
</span>
Answer
For this we use ideal gas equation which is:
P1V1 = P2V2
P1 = 1.10 atm
V1 = 326 ml
P2 = 1.90
V2 = ?
By rearranging the ideal gas equation:
V2 = P1V1 ÷ P2
V2 = 1.10 × 326 ÷1.90
V2 = 358.6 ÷ 1.90
V2 = 188.7 ml
Answer:
PART A: 412.98 nm
PART B: 524.92 nm
Explanation:
The equation below can be used for a diffraction grating of nth order image:
n*λ = d*sinθ
Therefore, for first order images, n = 1 and:
λ = d*sinθ.
The angle θ can be calculated as follow:
tan θ = 9.95 cm/15.0 cm = 0.663 and
θ = (0.663) = 33.56°
Thus: d =λ/sin θ = 461/sin 33.56° = 833.97 nm
PART A:
For a position of 8.55 cm:
tan θ = 8.55 cm/15.0 cm = 0.57 and
θ = (0.57) = 29.68°
Therefore:
λ =d*sin θ = 833.97*sin 29.68° = 412.98 nm
PART B:
For a position of 12.15 cm:
tan θ = 12.15 cm/15.0 cm = 0.81 and
θ = (0.81) = 39.01°
Therefore:
λ =d*sin θ = 833.97*sin 39.01° = 524.92 nm
The answer is pH = 4.6. Methyl orange would turn yellow if the pH is above 4 and methyl red turns red when the pH level is below 5. So, it should be PH = 4.6<span>
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Answer:
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Explanation:
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