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almond37 [142]
3 years ago
8

What happens when the forces are applied on an object in the same direction ?

Physics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

if the object is already moving and a force is applied in the same direction, the object will speed up or accelerate.

hope this helped :)

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Two identical bowling balls are rolling on a horizontal floor without slipping. The initial speed of both balls is v = 10 m/s. B
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Answer:

The difference between frictionless ramp and a regular ramp is that on a frictionless ramp the ball cannot roll it can only slide, but on a regular ramp the ball can roll without slipping.

We will use conversation of energy.

K_A_1 + U_A_1 = K_A_2 + U_A_2\\\frac{1}{2}I\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_A

Note that initial potential energy is zero because the ball is on the bottom, and the final kinetic energy is zero because the ball reaches its maximum vertical distance and stops.

For the ball B;

K_B_1 + U_B_1 = K_B_2 + U_B_2

\frac{1}{2}I_B\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_B

The initial velocities of the balls are equal. Their maximum climbing point will be proportional to their final potential energy. Since their initial kinetic energies are equal, their final potential energies must be equal as well.

Hence, both balls climb the same point.

Explanation:

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3 years ago
7. The energy source used to produce most of the electrical energy in the United States is ____________________.
Fudgin [204]

Fossil fuels like coal, natural gas and oil.

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Question 9 of 10
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I believe the correct answer is B..<u>" 1 "</u>

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A bullet fired horizontally hits the ground in 0.5 sec. If it had been fired with a much higher speed in the same direction, and
stira [4]

Answer:

3. 0.5 sec.

Explanation:

A bullet fired horizontally follows a projectile motion, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with  constant acceleration, g = 9.8 m/s^2, towards the ground

The time taken for the bullet to reach the ground can be calculated just by considering the vertical motion:

y(t) = h + v_{0y} t - \frac{1}{2}gt^2

where y is the vertical position at time t, h is the initial height, and v_{0y} is the initial vertical velocity of the bullet.

Since the bullet is fired horizontally, v_{0y}=0. So the equation becomes

y(t) = h - \frac{1}{2}gt^2

And the time that the bullet takes to reach the ground can be found by requiring y=0 and solving for t:

t=\sqrt{\frac{2h}{g}}

As we can see, in this equation there is no dependance on the initial speed of the bullet: therefore, if the bullet is fired still horizontally but with a different speed, it will still take the same time (0.5 s) to reach the ground.

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