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Citrus2011 [14]
3 years ago
12

3. All the following steps need to be followed when naming alkanes, except A. locating the longest carbon chain. B. using prefix

es to designate identical branches. C. placing the name in alphabetic order ignoring the added prefixes. D. beginning numbering at the end farther from the first branch.
Chemistry
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

D. beginning numbering at the end farther from the first branch.

Explanation:

In naming alkanes, the longest continuous chain in the compound is first considered and this gives the name of the compound intended. The name of the substituent on the compound are also arranged in alphabetical order when naming the compound.

The carbon atoms are numbered in the parent chain or ring to indicate where branching or substitution takes place. The direction of numbering is chosen such that the lowest numbers possible is given to the branches or substituents. If we begin the numbering at the end farther from the first branch, we won't give the lowest numbers possible to the branches.

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1.72 mol of LiCl in 37.5 L of solution
givi [52]
<h3>Answer:</h3>

Molarity is 0.046 M

<h3>Explanation:</h3>

We are given;

1.72 mol of LiCl in 37.5 L of solution

We will take the question to be; calculate the molarity of LiCl

Therefore,

we can start by defining molarity as the concentration of a solution in moles per liter.

Molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution.

Molarity = Moles of solute ÷ Volume of the solution

Thus, in this case;

Molarity of LiCl = Moles of LiCl ÷ Volume of the solution

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Therefore, the molarity of LiCl solution is 0.046 M

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Natalka [10]

Answer:

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