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Citrus2011 [14]
4 years ago
12

3. All the following steps need to be followed when naming alkanes, except A. locating the longest carbon chain. B. using prefix

es to designate identical branches. C. placing the name in alphabetic order ignoring the added prefixes. D. beginning numbering at the end farther from the first branch.
Chemistry
1 answer:
gulaghasi [49]4 years ago
8 0

Answer:

D. beginning numbering at the end farther from the first branch.

Explanation:

In naming alkanes, the longest continuous chain in the compound is first considered and this gives the name of the compound intended. The name of the substituent on the compound are also arranged in alphabetical order when naming the compound.

The carbon atoms are numbered in the parent chain or ring to indicate where branching or substitution takes place. The direction of numbering is chosen such that the lowest numbers possible is given to the branches or substituents. If we begin the numbering at the end farther from the first branch, we won't give the lowest numbers possible to the branches.

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How many moles are in 7.8 g of acetamide, CH3CONH2?
atroni [7]

Answer:

.13 moles

Explanation:

To begin this problem:

First you need to find the molar mass of acetamide, to do so:

  • C=12g, H=1.008g, O=16g, and N=14g
  • 2(12)+5(1.008)+1(16)+1(14)=59.04

To find moles when given grams, we divide grams by the molar mass.

  • 7.8g/59.04g/mol=.13 moles

Using 2 sig figs from what we are given, this is our final answer.

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2 years ago
What structural units make up network solids
zheka24 [161]
Nonmetal Atom is the answer.
5 0
3 years ago
12 G of carbon react with 16 G of oxygen how much carbon monoxide is formed ​
elena55 [62]

Answer:

28 g CO

Explanation:

First convert grams to moles.

1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)

12 g C • \frac{1 mol C}{12 g C} = 1 mol C

1 mol O = 15.996 g (I'm just going to round to 16)

16 g O • \frac{1 mol O}{16 g O} = 1 mol O

So the unbalanced equation is:

C + O_{2} -> CO (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)

The balanced equation is:

2 C + O_2 -> 2 CO

However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation

C + \frac{1}{2} O_2 -> CO.

1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.

3 0
3 years ago
What does percent composition tell you about a substance?
beks73 [17]

Answer:

Percent composition tells you which types of atoms (elements) are present in a molecule and their levels. Percent composition can also tell you about the different elements present in an ionic compound as well.

8 0
3 years ago
Nitrogen forms more oxides than any other element. The percents by mass of in three different nitrogen oxides are (1) (II) and (
Tema [17]

Complete question;

Nitrogen forms more oxides than any other element. The percents by mass of N in three different nitrogen oxides are (|) 46.69%;(II) 36.85 %; (III) 25.94%. For each compound, determine (a) the simplest whole-number ratio of N to O, and (b) the number of grams of oxygen per 1.00 g of nitrogen.

Answer:

a. (i) The ratio is 1:1 , the formula = NO  (ii)The ratio is 1 : 1.5 which is  2 : 3, the formula = N₂O₃  (iii) The ratio is 1 : 2.5 which is 2:5 , the formula = N₂O₅

b. (i)number of grams of oxygen = 53.31/46.69 = 1.14 g

(ii)number of grams of oxygen = 63.15/36.8 = 1.71 g

(iii)number of grams of oxygen = 74.06/25.94 = 2.855 g

Explanation:

a.

(i) The percentage by mass of the nitrogen in Nitrogen oxide (i) is 46.69% which is taken as 46.69 grams . Since the other element is oxygen the mass of oxygen will be 100 - 46.69 = 53.31 grams.

The relative atomic mass of Nitrogen and oxygen is 14 amu and 16 amu respectively.

Therefore, to know the whole number ratio of N and O we find the number of moles.

number of moles of N = 46.69/14 = 3.335

number of moles of O = 53.31/16 = 3.332

The ratio is 1:1 , the formula = NO

(ii)

number of moles of N = 36.85/14 = 2.632

number of moles of O = 63.15/16 = 3.947

The ratio is 1 : 1.5 which is  2 : 3, the formula = N₂O₃

(iii)

number of moles of N = 25.94/14 = 1.85

number of moles of O = 74.06/16 = 4.63

The ratio is 1 : 2.5 which is 2:5 , the formula = N₂O₅

b.

(i) 46.69 g of nitrogen  = 53.31 g of oxygen

1 g of nitrogen = ? of Oxygen

number of grams of oxygen = 53.31/46.69 = 1.14 g

(ii)

Using similar method in b(i)

number of grams of oxygen = 63.15/36.8 = 1.71 g

(iii)

Using similar method in b(i)

number of grams of oxygen = 74.06/25.94 = 2.855 g

3 0
3 years ago
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