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Citrus2011 [14]
4 years ago
12

3. All the following steps need to be followed when naming alkanes, except A. locating the longest carbon chain. B. using prefix

es to designate identical branches. C. placing the name in alphabetic order ignoring the added prefixes. D. beginning numbering at the end farther from the first branch.
Chemistry
1 answer:
gulaghasi [49]4 years ago
8 0

Answer:

D. beginning numbering at the end farther from the first branch.

Explanation:

In naming alkanes, the longest continuous chain in the compound is first considered and this gives the name of the compound intended. The name of the substituent on the compound are also arranged in alphabetical order when naming the compound.

The carbon atoms are numbered in the parent chain or ring to indicate where branching or substitution takes place. The direction of numbering is chosen such that the lowest numbers possible is given to the branches or substituents. If we begin the numbering at the end farther from the first branch, we won't give the lowest numbers possible to the branches.

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Answer:

Frequency = Velocity / Wavelength = 100 m/s / 20 m = 5 s-1 or 5 Hz.

Explanation:

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3 years ago
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What do the water cycle and wind have in common
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The water cycle deals with wind. The wind uses up energy as well as the water cycle. 
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3 years ago
A solution is prepared by dissolving 0.7234 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq
marishachu [46]

Answer: The final molarity of the diluted oxalic acid solution is 0.0032 M

Explanation:

Molarity: It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.7234g}{90g/mol}=0.008moles

V_s = volume of solution in ml

Molarity=\frac{0.008\times 1000}{100.0}=0.08

To calculate the final molarity of the diluted oxalic acid solution

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of concentrated oxalic acid solution.

M_2\text{ and }V_2 are the molarity and volume of diluted oxalic acid solution.

We are given:

M_1=0.08\\V_1=10.00mL\\M_2=?\\V_2=250.0mL

Putting values in above equation, we get:

0.08\times 10.00=M_2\times 250.0\\\\M_2=0.0032M

Thus the final molarity of the diluted oxalic acid solution is 0.0032 M

8 0
3 years ago
Even though lead is toxic, lead compounds were used in ancient times as white pigments in cosmetics. What is the percentage of l
Gekata [30.6K]

<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %

<u>Explanation:</u>

The given chemical formula of lead (IV) carbonate is Pb(CO_3)_2

To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100

Mass of lead = (1 × 207.2) = 207.2 g

Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

Putting values in above equation, we get:

\text{Mass percent of lead}=\frac{207.2g}{327.2g}\times 0100=63.32\%

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %

4 0
3 years ago
Which of these substances has the highest pOH? 0.10 M HCl, pH = 1 0.001 M HNO3, pH = 3 0.01 M NaOH, pH = 12 The answer is 0.10 M
Naya [18.7K]

Answer:On these combined scales of pH and pH it can be shown that because for water when pH = pH = 7 that pH + pH = 14. This relationship is useful in the inter conversion of values. For example, the pH at a 0.01 M solution of sodium hydroxide is 2, the pH of the same solution must be 14-2 = 12.

Explanation:

4 0
3 years ago
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