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2 years ago

Why does potassium explode when exposed to water?

Chemistry

1 answer:

soldi70 [24.7K]2 years ago

4 0

Answer:

The highly unstable pure sodium or potassium wants to lose an electron and this splits the water atom, producing a negatively charged hydroxide ion and hydrogen and forming an explosive gas that ignites.

Explanation:

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2 years ago

. The net ionic equation for the reaction that occurs during the titration of nitrous acid with sodium hydroxide is (a) HNO2 Na

hjlf

Answer:

$H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}$

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Only the species which are present in aqueous state dissociate.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a)

The balanced molecular equation will be,

$HNO_2_{(aq)}+NaOH_{(aq)}\rightarrow H_2O_{(l)}+NaNO_2_{(aq)}$

The complete ionic equation in separated aqueous solution will be,

$H^+_{(aq)}+NO_2^-_{(aq)}+Na^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+Na^+_{(aq)}+NO_2^-_{(aq)}$

In this equation the species present are, $Na^+\text{ and }NO_2^-$ are the spectator ions.

Hence, the net ionic equation contains specie is

$H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}$

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2 years ago

At 500 K, the reaction is at equilibrium with the following concentrations. [PCI5]= 0.0095 M [PCI3] = 0.020 [CI2] = 0.020 M What

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Although it is omitted, the reaction equation for the decomposition of phosphorus pentachloride is:
PCl₅ → PCl₃ + Cl₂

The equilibrium constant's equation then becomes:
Kc = [PCl₃]*[Cl₂] / [PCl₅]
Kc = (0.02 * 0.02) / 0.0095
Kc = 0.042

The equilibrium constant is 0.042.

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It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj

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