Answer:
opt a f g is correct answer ok
Ideal gasses (ideal gas law)
Answer:
2.83 g
Explanation:
At constant temperature and pressure, Using Avogadro's law
Given ,
V₁ = 2.12 L
V₂ = 3.12 L
n₁ = 0.120 moles
n₂ = ?
Using above equation as:
n₂ = 0.17660 moles
Molar mass of methane gas = 16.05 g/mol
So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g
<u>2.83 g are in the piston.</u>
Answer: 8.45 L
Explanation:
Given that,
Initial volume (V1) = 3.5L
Initial pressure (P1) = 2.5 atm
[Since final pressure is given in torr, convert 2.5 atm to torr
If 1 atm = 760 torr
2.5 atm = 2.5 x 760 = 1900 torr
Final volume (V2) = ?
Final pressure (P2) = 787 torr
Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law
P1V1 = P2V2
3.5L x 1900 torr = 787 torr x V2
6650L•torr = 787 torr•V2
Divide both sides by 787 torr
6650L•torr/787 torr = 787 torr•V2/787 torr
8.45 L = V2
Thus, the volume of the gas at 787 torr and at the same temperature is 8.45 Liters
Explanation:
1. K (Potassium)
2. Te (Tellurium)
3. F (Flourine)
4. group 11, period 4
5. group 18, period 4
6. group 12, period 6
7. Cl
8. Pb
9. W
10. Sb
11. Na
12. period 6, group 11
13. period 5, group 11
14. period 2, group 16
15. Groups 13–16 of the periodic table contain one or more metalloids
16. Hydrogen
17. Helium
18. Calcium
19. Cobalt
20. Carbon
