Using the relationship M1V1 = M2V2 where M1 and M2 are the molar concentrations (mol/L or mmol/ml) and V1 and V2 are the volumes of the solutions, we can arrive at the following answer for the given problem:
<span>15.0M (L of stock solution) = 2.35M (0.25L) *all volumes were converted to liters.
L of stock solution = (2.35*0.25)/15.0
Therefore, 0.0392L or 39.17 ml of stock solution is needed. </span>
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At conditions 50 K and 20 kPa of temperature and pressure
would helium behave most like an ideal gas. The answer is number 1. This is because
the temperature is so low and the pressure is low too.
Answer:
The correct answer is = 31.04
Explanation:
The relation between volume, temperature and pressure of a fix amount of a gas can be expressed by the combined gas law:
PV/T = k
It can be written as well as
P1V1/T1 = P2V2/T2
Given:
V1 = 217.6
P1 = 9.011 atm
T1 = 127.8°C = 400.95 K
P2 = 44.9
T2 = 11.9 °C = 285.05
Solution:
Putting value in the formula
V2 = P1V1T2/P2T1
= (217.6*285.05*9.011)/44.9*400.95
V2 = 31.04
Answer:
0.925 atm
Explanation:
By Dalton's Law, the total pressure of a gas mixture is the sum of the partial pressure of its components. The vapor pressure of the water is the pressure that some molecules that evaporated do under the liquid surface. The gas and the liquid are at equilibrium. So, the gas mixture is water vapor and hydrogen gas.
Ptotal = Pwater + PH₂
745 = 42 + PH₂
PH₂ = 703 torr
Transforming to atm:
1 atm ------------------760 torr
x ------------------ 703 torr
By a simple direct three rule
760x = 703
x = 0.925 atm