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Andrei [34K]
3 years ago
10

Please help asap! Brainliest to correct.

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

Pilar

Step-by-step explanation:

If you rotate it, you get the same graph.  

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Need help ASAP! (Geometry 1)
melisa1 [442]

Answer:

The Length of third side is 52 units.

Step-by-step explanation:

Given:

Length of First side = 48

Length of second side = 20

Also given the angle between them is 90°.

Hence we can say figure shown is a right angled triangle.

For finding the third side we can use Pythagoras theorem which states that;

"If a triangle is right angled then, the Square of the hypotenuse is equal to sum of the square of the other two sides."

Third \ side ^2=First \ side^2+Second \ side^2

Hence substituting the values we get;

Third\ side^2= 48^2+20^2 = 2304+400 =2704

Now taking Square root on both side we get;

\sqrt{Third \ side^2} = \sqrt{2704}\\ Third \ side = 52 \ units

Hence Length of Third side is 52 units.

3 0
4 years ago
Solve for x. Round to the nearest tenth.
ivanzaharov [21]

x ≈ 59°

Work is on piece of paper, yet I don't have a phone. I'm certain that is the answer.

5 0
3 years ago
How can you use the properties of operations to evaluate<br> this expression?<br> 18 + 4(28)
pentagon [3]

Answer:

first open the bracket by multiplying 28 by 4 which is equal to 112, then add it to 18 which be equal to 130 which is the final answer

5 0
3 years ago
Read 2 more answers
I need to know the answer please , thank you !
n200080 [17]
The answer is D your welcome
3 0
3 years ago
The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de
antoniya [11.8K]

Answer:

a) P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b) P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c) P(A') = 1-P(A) =1-0.4=0.6

d) P(A \cup B) =0.4 +0.8-0.2 =1.0

e)  The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

Step-by-step explanation:

We have the following space provided:

S= [a,b,c,d,e]

With the following probabilities:

P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

P(A) = 0.1+0.1+0.2 = 0.4

P(B) =0.2+0.4+0.2=0.8

Determine:

a. P(A)

P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b. P(B)

P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c. P(A’)

From definition of complement we have this:

P(A') = 1-P(A) =1-0.4=0.6

d. P(AUB)

Using the total law of probability we got:

P(A \cup B) =P(A) +P(B)-P(A \cap B)

For this case P(A \cap B) = P(c) =0.2, so if we replace we got:

P(A \cup B) =0.4 +0.8-0.2 =1.0

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

8 0
3 years ago
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