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2 years ago

Describe how the metal case of an electrical appliance is connected to earth

Physics

2 answers:

Misha Larkins [42]2 years ago

7 0

Anything that is medal is connected to earth

Pachacha [2.7K]2 years ago

3 0

This happens through the connection cord, that has 3 wires: 2 wires are used for power supply. The third wire is used to 'ground' the metal case, by connecting it to a special pin from the wall socket. The eletrical installation of the building connects all these ground pins to earth.

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A rope vibrates every 0.5 s. what is the frequency of the waves?

umka2103 [35]

F = 1/t
F = 1/0.5
F = 2Hz

Answer is 2Hz

4 0

3 years ago

Read 2 more answers

By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what

Vinil7 [7]

Explanation:

1. Mass of the proton, $m_p=1.67\times 10^{-27}\ kg$

Wavelength, $\lambda_p=4.23\times 10^{-12}\ m$

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}$

$V=\dfrac{h^2}{2q_pm_p\lambda^2}$

$V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}$

V = 45.83 volts

2. Mass of the electron, $m_p=9.1\times 10^{-31}\ kg$

Wavelength, $\lambda_p=4.23\times 10^{-12}\ m$

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}$

$V=\dfrac{h^2}{2q_em_e\lambda^2}$

$V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}$

$V=6.92\times 10^{34}\ V$

V = 84109.27 volt

Hence, this is the required solution.

7 0

3 years ago

What is the value of 9682 when rounded to three significant figures

sdas [7]

9700 because 682 rounds to 700

5 0

3 years ago

What is the idea behind the law of multiple proportions?

Akimi4 [234]

Answer:

The law of multiple proportions states that when two elements can combine in different ratios to form different compounds, the masses of the element combining with the fixed mass of another element result in whole number ratios. This shows that the law of multiple proportions is followed

Explanation:

5 0

3 years ago

An object weighs 10N on earth .what is the objects weight on a planet one tenth the earths mass and one half its radius?

earnstyle [38]

We know, weight = mass * gravity
10 = m * 9.8
m = 10/9.8 = 1.02 Kg

Now, Let, the gravity of that planet = g'
g' = m/r² [m,r = mass & radius of that planet ]
g' = M/10 / (1/2R)² [M, R = mass & radius of Earth ]
g' = 4M / 10R²
g' = 2/5 * M/R²
g' = 2/5 * g
g' = 2/5 * 9.8
g' = 3.92

Weight on that planet = planet's gravity * mass
W' = 3.92 * 1.02
W' = 4 N

In short, Your Answer would be 4 Newtons

Hope this helps!

3 0

3 years ago