All categories

3 years ago

5. Which ordered-pair is a solution of the equation y = - 9x + 4

Mathematics

2 answers:

Citrus2011 [14]3 years ago

7 0

A.(10,-86) you would substitute this into the equation, which would be correct.

ipn [44]3 years ago

7 0

Answer:

A) (10, -86)

Step-by-step explanation:

Because (x, y)=(10, -86),

now plug in those values into the equation y=-9x+4.

You get -9(10)+4=-90+4=-86, which is the correct y-value.

Please mark me as Brainliest if you're satisfied with the answer.

You might be interested in

Which statement about the graph of y = 1/3(2/3)^x is true?

storchak [24]

Answer:

when you put in the calculator it starts from the top then gets closer to 0

6 0

3 years ago

Read 2 more answers

ABCD~LMNO Find the value of MN if AB=12cm, BC=9.6cm and LM= 16cm

Arturiano [62]

The answer is C

Explaining:

3 0

3 years ago

What is the solution to y = x + 2 and y = 3x – 2 and how do you know? PLEASE HELPPPPP! THANK U!

Nutka1998 [239]

Answer:

(2,4)

Step-by-step explanation:

We have the system:

y=x+2

y=3x-2.

This is already setup for substitution.

I'm going to replace my first y with what the second y equals.

That is, I'm going to write 3x-2=x+2.

Time to solve the following for x:

3x-2=x+2

Subtract x on both sides:

2x-2= 2

Add 2 on both sides:

2x. = 4

Divide both sides by 2:

x. = 2

Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.

So we y=x+2 with x=2 which means y=2+2=4.

So the solution, the intersection, is (2,4).

5 0

3 years ago

Read 2 more answers

Solve. - 1/3b = 9 A. -3 B. 3 C. - 27 D. 27

ruslelena [56]

$-\dfrac{1}{3}b=9\ \ \ |multiply\ both\ sides\ by\ (-3)\\\\-3\cdot\left(-\dfrac{1}{3}b\right)=-3\cdot9\\\\\huge\boxed{b=-27}\leftarrow\boxed{C}$

3 0

3 years ago

Read 2 more answers

Explain and demonstrate the multiplication of complex conjugates using 2+3i and its complex conjugate. Be sure to discuss all st

krok68 [10]

The product of a complex number and its conjugate is (a + i b) · (a - i b), where a and b are real numbers, and the result for the complex number 2 + i 3 is 13.

<h3>What is the multiplication of a complex number and its conjugate</h3>

Let be a complex number a + i b, whose conjugate is a - i b. Where a and b are real numbers. The product of these two numbers is:

(a + i b) · (a - i b)

Then, we proceed to obtain the result by some algebraic handling:

a · (a + i b) + (- i b) · (a + i b)

a² + i a · b - i a · b - i² b²

a² - i² b²

a² + b²

If we know that a = 2 and b = 3, then the product of the complex number and its conjugate is:

$z\cdot \bar z = 2^{2} + 3^{2}$

$z\cdot \bar z = 13$

To learn more on complex numbers: brainly.com/question/10251853

#SPJ1

6 0

2 years ago