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3 years ago

Explain feather and coin experiment (don't copy )

Physics

1 answer:

Neko [114]3 years ago

3 0

Answer:

A British scientist Robert Boyal performed an experiment about a feather and coin.

firstly he dropped a coin and a feather simultaneously ( together) in a jar in which the coin reached the bottom first .

again ,

he removed the atmosphere inside the jar by vaacum pump and then he again dropped the feather and coin simultaneously . now both the coin and feather reached the bottom together .

conclusion:

the acceleration produced on a body is the same for all the bodies and it does not depend upon the mass of the falling body.

hope this helped u☺️

any confusion then comment it.

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A lunar lander is descending toward the moon's surface. Until the lander reaches the surface, its height above the surface of th

NeX [460]

Answer:

Part A:

$v_y=-63 m/s$

Part B:

$v_y=-24.67792 m/s$

Explanation:

Part A:

The formula we are going to use is:

$v_{y}= \frac{dy(t)}{dt} \\v_y=\frac{d(b-ct+dt^2)}{dt} \\v_y=-c+2d*t$

For finding the initial velocity we put t=0 in above formula:

$v_y=-c+2d*t$

$v_y=-c+2d*0$

$v_y=-c$

c=63 So,

$v_y=-63 m/s$

Part B:

When lander reaches the lunar surface y(t)=0

$y(t)=b-ct+dt^2=0$

Using Quadratic formula:

$t=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

In our case:

$t=\frac{c\±\sqrt{c^2-4db} }{2d}$

$t=\frac{63\±\sqrt{(63)^2-4*1.05*800} }{2*1.05}$

$t=41.75139sec$ $t=18.248606sec$

We are going to choose t=18.248606 sec because it is smaller.

$v_y=-c+2d*t$ (Calculated above)

$v_y=-63+2(1.05)*18.248606$

$v_y=-24.67792 m/s$

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4 years ago

What are some predicted affects of climate change linked to global warming

Alla [95]

Decrease in atmospheric ozone, which results in lower protection from various stellar particles

5 0

3 years ago

Mars is known as Earth’s sister planet.

grigory [225]

1. True
2. Mercury
3. Jupiter
4. False its Jupiter than Saturn
5. False
6. True
7. I think maybe Venus sry don't know this one lol
8. Storm
9. Uranus

7 0

3 years ago

Use what you know about mass and how you use it to calculate force in the following situation. If each washer has a mass of 4. 9

mina [271]

Considering the change of units and the definition of weight, the mass of two washers would be 0.0098 kg and if 4 washers are attached to the string, then the applied force on the car will be 0.196 N.

Mass of two washers

If each washer has a mass of 4.9 g, then the mass of two washers will be calculated simply by multiplying the mass of 1 washer by the amount you have of them, in this case 2:

4.9 g×2= 9.8 g

Being 1 kg = 1000 g, you apply the following rule of three to make the change of units: if 1000 g equals 1 kg, 9.8 g equals how many kilograms?

$mass=\frac{9.8 gramsx1 kg}{1000g}$

Solving:

mass= 0.0098 kg

Finally, the mass of two washers would be 0.0098 kg.

Applied force

On the other side, mass is the amount of matter that a body contains and weight is the action exerted by the force of gravity on the body.

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

Weight is calculated as the product of the object's mass and the value of the gravitational acceleration:

W= m×g

In this case, you know:

m= 4.9 g×4= 19.6 g= 0.0196 kg → the mass of 4 washers in kilograms
g= 10 m/s²

Replacing:

W= 0.0196 kg× 10 m/s²

Solving:

W= 0.196 N

Finally, if 4 washers are attached to the string, then the applied force on the car will be 0.196 N.

Learn more:

7 0

3 years ago

Read 2 more answers

A car is traveling at 104 km/h when the driver sees an accident 50 m ahead and slams on the brakes. What minimum constant decele

Solnce55 [7]

Answer:

–8.35 m/s²

Explanation:

We'll begin by converting 104 km/h to m/s. This can be obtained as follow:

3.6 Km/h = 1 m/s

Therefore,

104 km/h = 104 km/h × 1 m/s / 3.6 Km/h

104 km/h = 28.89 m/s

Thus, 104 km/h is equivalent to 28.89 m/s.

Finally, we shall determine the deceleration of the car. This can be obtained as follow:

Initial velocity (u) = 28.89 m/s

Final velocity (v) = 0 m/s

Distance (s) = 50 m

Deceleration (a) =?

v² = u² + 2as

0² = 28.89² + (2 × a × 50)

0 = 834.6321 + 100a

Collect like terms

0 – 834.6321 = 100a

–834.6321 = 100a

Divide both side by 100

a = –834.6321 / 100

a = –8.35 m/s²

Thus, the deceleration of the car is –8.35 m/s².

5 0

3 years ago

Explain feather and coin experiment (don't copy )​

Explain feather and coin experiment (don't copy )