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avanturin [10]
3 years ago
9

Which catalyzed reaction breaks up ozone?

Chemistry
1 answer:
bekas [8.4K]3 years ago
4 0

This is a good example of homogeneous catalysis where everything is present as a gas.

Ozone, O3, is constantly being formed and broken up again in the high atmosphere by the action of ultraviolet light. Ordinary oxygen molecules absorb ultraviolet light and break into individual oxygen atoms. These have unpaired electrons, and are known as free radicals. They are very reactive.

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Use Lewis diagrams to show how electrons are shared to form covalent bonds in compounds wit the following atoms. Write the formu
bixtya [17]
The Lewis structure/diagram for CH2O (aka Formaldehyde) can be written in either of the following ways shown in the picture.
The dots represent electrons in the valence shell of the atom (the outermost shell). The green dots are electrons that belong to the Oxygen atom, the blue belong to the Carbon atom, and the pink belong to the Hydrogen atoms.
Covalent bonds are bonds between atoms where atoms share electrons with each other. Atoms bond because they obey the octet rule ( the rule states that most atoms of main-group elements tend to want 8 electrons in their valence shells). 
Oxygen has 6 valence electrons, Carbon has 4, and Hydrogen has 1. H does not follow the octet rule, but C and O do, so the atoms are arranged in this way so that the O and C atoms have a full octet of electrons in their valence.

8 0
2 years ago
Chemistry<br>oxidation number<br>​
zloy xaker [14]

Answer:

sodium proxide

Explanation:

3 0
2 years ago
For this discussion, respond to the following... An electron falls through a distance d in a uniform electric field of magnitude
mars1129 [50]

The electron should experience a greater acceleration due to it's significantly smaller mass and should fall through distance "d" in a shorter amount of time.

<u>Explanation:</u>

The electron force can be expressed as F=qE. According to Newton's second law of motion force can be expressed as F=ma. This can be written as a=F/m. Substituting electric force expression for "F" in this equation, we get a=qE/m. This means acceleration is conversely proportional to mass and directly to electric field and charge. This means that proton having significantly larger mass than electron should experience smaller amount of acceleration and would take longer to fall at distance "d".

On the other hand, the electron would experience greater acceleration due to it's significantly smaller mass and would fall faster at distance "d", unlike the situation of proton.

4 0
2 years ago
At 850K, 65L of gas has a pressure of 450kPa. What is the volume (in liters) if the gas is cooled to 430K and the pressure decre
Novosadov [1.4K]

Answer:

V₂ =  45.53 L

Explanation:

Given data:

Initial temperature = 850 K

Initial volume = 65 L

Initial pressure = 450 KPa

Final temperature = 430 K

Final pressure = 325 KPa

Final volume = ?

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa  

V₂ = 12577500 KPa .L. K / 276250 K. KPa

V₂ =  45.53 L

8 0
2 years ago
Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energ
SSSSS [86.1K]

<u>Answer:</u> The molecules of oxygen gas that will be reduced to water are 42 molecules

<u>Explanation:</u>

We are given:

E^o_{(NO_2^-/NH_4)}=-0.41V\\E^o_{(O_2/H_2O)}=0.82V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, oxygen will undergo reduction reaction will get reduced.

NH_4 will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

The half reactions follows:

<u>Oxidation half reaction:</u>  NH_4\rightarrow NO_2^-+6e^-     ( × 4)

<u>Reduction half reaction:</u>  O_2+4e^-\rightarrow 2H_2O   ( × 6)

<u>Overall reaction:</u> 4NH_4+6O_2\rightarrow 4NO_2^-+12H_2O

We are given:

Molecules of NH_4 = 28

By Stoichiometry of the reaction:

4 molecules of NH_4 reacts with 6 molecules of oxygen gas

So, 28 molecules of NH_4 will react with = \frac{6}{4}\times 28=42 molecules of oxygen gas

Hence, the molecules of oxygen gas that will be reduced to water are 42 molecules

4 0
3 years ago
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