Answer:
(a) t = 0.75 s
(b) d = 26 m
Explanation:
Height, h = 12 m
Angle, A = 30 degree
initial velocity, u = 40 m/s
(a) Let the time is t.
Use second equation of motion
(b) d = u cos A t
d = 40 x cos 30 x 0.75 = 26 m
No, because the word might offend that person.
No.
If they add together to get a vector of length zero they should make a triangle of loading.
The sides 1 m, 2 m and 4 m will not make a triangle since the sum of 1 and 2 is less than 4.
In the given figure a+b < c , so they make a triangle.
Here this condition is not satisfied.
Answer:
a) F = 2.7 10⁻¹⁴ N
, b) a = 2.97 10¹⁶ m / s² c) θ = 14º
Explanation:
The magnetic force on the electron is given by the expression
F = q v x B
Which can be written in the form of magnitude and the angle found by the rule of the right hand
F = q v B sin θ
where θ is the angle between the velocity and the magnetic field
a) the maximum magnitude of the force occurs when the velocity and the field are perpendicular, therefore, without 90 = 1
F = e v B
F = 1.6 10⁻¹⁹ 2.40 10⁶ 7.10 10⁻²
F = 2.73 10⁻¹⁴ N
F = 2.7 10⁻¹⁴ N
b) Let's use Newton's second law
F = m a
a = F / m
a = 2.7 10⁻¹⁴ / 9.1 10⁻³¹
a = 2.97 10¹⁶ m / s²
The actual acceleration (a1) is a quarter of this maximum
a1 = ¼ a
a1 = 7.4 10¹⁵ m / s²
With this acceleration I calculate the force that is executed on the electron
F = ma
e v b sin θ= ma
sin θ = ma / (e v B)
sin θ = 9.1 10⁻³¹ 7.4 10¹⁵ / (1.6 10⁻¹⁹ 2.40 10⁶ 7.10 10⁻²)
sin θ = 6.734 10⁻¹⁵ / 27.26 10⁻¹⁵
sin θ = 0.2470
θ = 14.3º