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3 years ago

What is 680 000 km as an integer?

Chemistry

1 answer:

stellarik [79]3 years ago

7 0

Answer:

INTEGER EXPANDED FORM

❤600000+80000❤

GLAD to HELP

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The stability of an atom is determined by the

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Ratio of neutrons to protons and <span>number of electrons in the outer shell</span>

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3 years ago

Read 2 more answers

Coal gasification is a multistep process to convert coal into cleaner-burning fuels. In one step, a coal sample reacts with supe

ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(a) The formation of $CH_4$ will be,

$2C(coal)+2H_2O(g)\rightarrow CH_4(g)+CO_2(g)$ $\Delta H_{rxn}=?$

The intermediate balanced chemical reaction will be,

(1) $C(coal)+H_2O(g)\rightarrow CO(g)+H_2(g)$ $\Delta H_1=29.7kJ$

(2) $CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)$ $\Delta H_2=-41kJ$

(3) $CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$ $\Delta H_3=-206kJ$

We are multiplying equation 1 by 2 and then adding all the equations, we get :

(b) The expression for enthalpy of reaction will be,

$\Delta H_{rxn}=2\times \Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H_{rxn}=(2\times 29.7)+(-41)+(-206)$

$\Delta H_{rxn}=-187.6kJ/mol$

Therefore, the enthalpy of reaction is, -187.6 kJ/mol

(c) Now we have to calculate the total heat.

$\Delta H=\frac{q}{n}$

or,

$q=\Delta H\times n$

where,

$\Delta H$ = enthalpy change = -187.6 kJ/mol

q = heat = ?

n = number of moles of coal = $\frac{1.00\times 1000g}{12.00g/mol}=83.33mol$

Now put all the given values in the above formula, we get:

$q=(-187.6kJ/mol)\times (83.33mol)=-2.251kJ$

Thus, the total heat will be, -2251 kJ

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4 years ago

The rate of formation of C in the reaction 2 A + B →2 C + 3 D is 2.7 mol dm−3 s −1 . State the reaction rate, and the rates of f

Zielflug [23.3K]

Answer:

Rate of reaction = $1.35mol.dm^{-3}.s^{-1}$

Rate of consumption of A = $2.7mol.dm^{-3}.s^{-1}$

Rate of consumption of B = $1.35mol.dm^{-3}.s^{-1}$

Rate of formation of D = $4.15mol.dm^{-3}.s^{-1}$

Explanation:

According to laws of mass action for the given reaction,

$Rate= -\frac{1}{2}\frac{\Delta [A]}{\Delta t}=-\frac{\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}=\frac{1}{3}\frac{\Delta [D]}{\Delta t}$

where, $-\frac{\Delta [A]}{\Delta t}$ is rate of consumption of A, $-\frac{\Delta [B]}{\Delta t}$ is rate of consumption of B, $\frac{\Delta [C]}{\Delta t}$ is rate of formation of C and $\frac{\Delta [D]}{\Delta t}$ is rate of formation of D

Here $\frac{\Delta [C]}{\Delta t}=2.7mol.dm^{-3}.s^{-1}$

So, Rate of reaction = $(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}$

Rate of formation of D = $(\frac{3}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{3}{2}\times 2.7mol.dm^{-3}.s^{-1})=4.15mol.dm^{-3}.s^{-1}$

Rate of consumption of A = $(\frac{2}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{2}{2}\times 2.7mol.dm^{-3}.s^{-1})=2.7mol.dm^{-3}.s^{-1}$

Rate of consumption of B = $(\frac{1}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}$

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3 years ago

The decomposition of kclo3 proceeds spontaneously when it is heated. do you think that the reverse reaction, the formation of kc

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<span>The answer is No, it is not possible that the reverse reaction will occur at ordinary conditions. This is because the entropy of the KCl and the O2 are much largely negative than that of the KClO3. The entropy component of the Gibbs free energy assures that the Gibbs free energy for the reverse reaction is positive (Positive Gibbs means nonspontaneous reaction). </span>

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4 years ago

Write the empirical formula for at least four ionic compounds ca2+.v5+,f-,s2

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Using these Elements. Here would be the 4 ionic compounds.

CaF2
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4 years ago