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3 years ago

True or false : More sunspots mean more energy comes from the sun

2 answers:

7 0

The answer is True: sunspots are one effect of increased activity on the Sun, so if there are more sunspots then there is more activity produced by the sun causing more energy to be created, I hope this helped!!!!! goodluck!!!! :)

RoseWind [281]3 years ago

6 0

True, hope this helps

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How can you use climatograph in a sentence? How can you use ecozone in a sentence?

Sav [38]

Ecozone is the broadest biogeographic division of the Earth's land surface, based on distributional patterns of terrestrial organisms. A climatograph is used to show the precipitation and the temperature of a region.

5 0

3 years ago

The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I

erma4kov [3.2K]

Answer:

Part a)

$I_{end} = \frac{mL^2}{3}$

Part b)

$I_{edge} = \frac{2ma^2}{3}$

Explanation:

As we know that by parallel axis theorem we will have

$I_p = I_{cm} + Md^2$

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

$I = \frac{mL^2}{12}$

now if we need to find the inertia from its end then we will have

$I_{end} = I_{cm} + Md^2$

$I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2$

$I_{end} = \frac{mL^2}{3}$

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

$I = \frac{ma^2}{6}$

now if we need to find the inertia about an axis passing through its edge

$I_{edge} = I_{cm} + Md^2$

$I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2$

$I_{edge} = \frac{2ma^2}{3}$

7 0

4 years ago

Gravitational force is determined by which of the following

hram777 [196]

Gravitational force is determined by mass

Answer: Option B

Explanation:

According to Universal law of gravity, the gravitational force is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the objects.

$F=G \times \frac{m_{1} \times m_{2}}{r^{2}}$