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MAXImum [283]
4 years ago
12

I'm not really sure how to go about creating the equation, can anyone help me?

Physics
1 answer:
AlexFokin [52]4 years ago
3 0
The displacement vector (SI units) is
\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}

The speed is a scalar quantity. Its magnitude is
v= \sqrt{A^{2}t^{2}+A^{2}(t^{3}-6t^{2})^{2}} \\ v=A \sqrt{t^{2}+t^{6}-12t^{5}+36t^{4}} \\ v=At \sqrt{t^{4}-12t^{3}+36t^{2}+1}

Answer: At√(t⁴ - 12t³ + 36t² + 1)
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The electronegativity of nonmetals is relatively __________ as compared to the electronegativity of metals.
solniwko [45]
Higher

Electronegativity generally increases from the left of the P.T.(metals) to the right (nonmetals).
7 0
3 years ago
How mesuremerment of gravity using simple pendulum <br>​
ale4655 [162]

Answer:

See below

Explanation:

Set up your pendulum

  measure its length  and time the period ( you could time 100 of them and divide the time result by 100 to get the period, T)

    then use  

             T = 2 pi  sqrt (L/g)        T = period    L = length   g = gravity

6 0
2 years ago
A car accelerates uniformly in a straight line with acceleration 10m/s 2 and travels 150m in a time interval of 5s. How far will
spayn [35]

Explanation:

Given:

Acceleration of car = 10 m/s

Distance travelled in 5 sec = 150 m

To find:

Distance travelled in the next 5 seconds

Concept:

There are 2 ways to app this kind of questions .

Either , we can find the total distance travelled in 10 seconds and then subtract 150 m from it.

Whereas , you can find out the final velocity at the end of the 5th seconds. Using equation of motion, then get the distance travelled in next 5 seconds.

Calculation:

v² = u² + 2as

=> ( u + at)² = u² + 2as

=> u² + 2uat + a²t² = u² + 2as

=> 2uat + (at)² = 2as

=> 2u (10)(5) + (10 × 5)² = 2 (10)(150)

=> 100u = 3000 - 2500

=> 100u = 500

=> u = 5 m/s

Distance travelled in 10 seconds :

s = ut + ½at²

=> s = (5 × 10) + ½(10)(10)²

=> s = 50 + 500

=> s = 550 m

Distance travelled in the 2nd half will be :

d = 550 - 150

=> d = 400 m

So final answer is :

6 0
3 years ago
In figure 16-2 is the temperature of the material within the cylinder greatest during the intake stroke, compression stroke, pow
erastovalidia [21]
Technically, we have no way of knowing that without seeing Figure 16-2.
So the question should be reported for incomplete content.  But I'm
going to take a wild stab at it anyway.

There's so much discussion of 'cylinder' and 'strokes' in the question,
I have a hunch that it's talking about the guts of a 4-stroke internal
combustion gasoline engine. 

If I'm right, then the temperature of the material within the cylinder is
greatest right after the spark ignites it.  At that instant, the material burns, 
explodes, expands violently, and drives the piston down with its stiff shot
of pressure.

This is obviously happening because of the great, sudden increase in
temperature when the material ignites and explodes.

It hits the piston with pressure, which leads directly to the power stroke.  
 
5 0
3 years ago
An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction
DiKsa [7]
Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
       = m(u/2)²
       = (1/4)mu²
      = (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer:  1/2 

5 0
4 years ago
Read 2 more answers
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