Answer:
the speed of the electron at the given position is 106.2 m/s
Explanation:
Given;
initial position of the electron, r = 9 cm = 0.09 m
final position of the electron, r₂ = 3 cm = 0.03 m
let the speed of the electron at the given position = v
The initial potential energy of the electron is calculated as;
When the electron is 3 cm from the proton, the final potential energy of the electron is calculated as;
Apply the principle of conservation of energy;
ΔK.E = ΔU
Therefore, the speed of the electron at the given position is 106.2 m/s
Force on -7 uC charge due to charge placed at x = - 10cm
now we will have
towards left
similarly force due to -5 uC charge placed at x = 6 cm
now we will have
towards left
Now net force on 7 uC charge is given as
towards left
1.47x10^5 Joules
The gravitational potential energy will be the mass of the object, multiplied by the height upon which it can drop, multiplied by the local gravitational acceleration. And since it started at the top of a 60.0 meter hill, halfway will be at 30.0 meters. So
500 kg * 30.0 m * 9.8 m/s^2 = 147000 kg*m^2/s^ = 147000 Joules.
Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.
Answer:
66.7%
Explanation:
There are 6 pulleys, so the mechanical advantage is 6.
The theoretical force needed to overcome 1200 N is therefore:
1200 N / 6 = 200 N
The actual force is 300 N. So the efficiency is:
200 N / 300 N × 100% = 66.7%