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2 years ago

Write the Standard Form of the equation of each line given the slope and y-intercept.

Mathematics

1 answer:

Svetlanka [38]2 years ago

8 0

Standard form: x-y = -3
x & y have to be whole numbers
x has to be positive

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Round 71290 to the nearest ten

marissa [1.9K]

It is already rounded to the tens because there is no digit but 0 in the ones digit. I hope this helped.

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3 years ago

Order of operations, step by step 56-12 / 6+4

icang [17]

Answer:

Step-by-step explanation:

Order of operations:

Parentheses
Exponents
Multiplication-Division
Addition-Subtraction

Solve:

56-12 / 6+4

56 - (12/6) +4 { No Multiplication but do have Division} (12/6 = 2)

56 - 2 + 4 {Subtraction ⇒ 56-2 = 54}

54 + 4 { Addition ⇒ 54 + 4 = 58}

Answer = 58

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2 years ago

3 times the difference between ten times a number and three is eighty one? Find the number

bixtya [17]

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2 years ago

FEE

frozen [14]

Answer:

The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

Given the line

3x - 4y = 7

writing in the slope-intercept form

4y = 3x - 7

dividing both sides by 4

4y/4 = 3/4x - 7/4

y = 3/4x - 7/4

Now, comparing with the slope-intercept form of the line equation

y = 3/4x - 7/4

The slope of the line m = 3/4

We know that parallel lines have the same slopes.

Therefore, the slope of the parallel line is: 3/4

now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

$\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)$

$y+2=\frac{3}{4}\left(x+4\right)$

Thus, the equation in the point-slope form of the line equation is:

$y+2=\frac{3}{4}\left(x+4\right)$

Simplifying the equation

$y+2=\frac{3}{4}\left(x+4\right)$

Subtract 3 from both sides

$y+2-2=\frac{3}{4}\left(x+4\right)-2$

$y=\frac{3}{4}x+1$

Multiplying the equation by 4

$4y = 3x + 4$

$3x - 4y = -4$

Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

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2 years ago

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Sergio039 [100]

Answer:

Step-by-step explanation:

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1 year ago