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GalinKa [24]
3 years ago
15

What isotope is the product of the alpha (*2He) nuclear decay of Radon-222 (222U)?

Chemistry
1 answer:
NikAS [45]3 years ago
3 0

Answer:

ⁿₐX => ²¹⁸₈₄Po

Explanation:

Let ⁿₐX be the isotope.

Thus, the equation can be written as follow:

²²²₈₆Rn —> ⁴₂α + ⁿₐX

Next, we shall determine the value of 'n' and 'a'. This can be obtained as follow:

222 = 4 + n

Collect like terms

222 – 4 = n

218 = n

Thus,

n = 218

86 = 2 + a

Collect like terms

86 – 2 = a

84 = a

Thus,

a = 84

ⁿₐX => ²¹⁸₈₄Po

²²²₈₆Rn —> ⁴₂α + ⁿₐX

²²²₈₆Rn —> ⁴₂α + ²¹⁸₈₄Po

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The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
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Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
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Molar mass of Na₂CO₃ = 106 g mol⁻¹

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                                        = 703540.02 g
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Answer:

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