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ruslelena [56]
2 years ago
5

A cylinder of argon contains 50 L of Ar at 12.4 atm and 127°C . How many moles of argon are in the cylinder

Chemistry
1 answer:
joja [24]2 years ago
6 0

Answer:

18.9 moles

Explanation:

We have the following data:

V = 50 L

P = 12.4 atm

T= 127°C + 273 = 400 K

R = 0.082 L.atm/K.mol (it is the gas constant)

We use the ideal gas equation to calculate the number of moles n of the gas:

PV = nRT

⇒ n = PV/RT = (12.4 atm x 50 L)/(0.082 L.atm/K.mol x 400 K) = 18.9 mol

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3 years ago
What is the Molar Mass of methylammonium bromide: Use the Periodic Table and round to the nearest hundredths.
egoroff_w [7]

The molar mass of methylammonium bromide is 111u.

<h3>What is molar mass?</h3>

The molar mass is defined as the mass per unit amount of substance of a given chemical entity.

Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.

Add it all together and put units of grams/mole after the number.

Atomic weight of H is 1u

Atomic weight of N is  14u

Atomic weight of C is  12u

Atomic weight of Br is  79u

Calculating molar mass of  2H_3NCH_3Br =2(1 x3+ 14+12+ 1 x 3 +79) = 111u

Hence, the molar mass of methylammonium bromide is 111u.

Learn more about molar mass here:

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1 year ago
Artificial intelligence is being used to protect which species of elephant
Nookie1986 [14]

Answer:

asian

Explanation:

because

5 0
3 years ago
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Which mineral has the same hardness as a fingernail?
Marina86 [1]
Gypsum has the same hardness as a fingernail
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3 years ago
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The equilibrium constant for the reaction 2NO(g)+Br2(g)⥫⥬==2NOBr(g) is Kc=1.3×10−2 at 1000 K. At this temperature does the equil
o-na [289]

Answer :

The equilibrium favors NO and Br_2.

(1) The value of equilibrium constant for this reaction is, 76.9

(2) The value of equilibrium constant for this reaction is, 8.77

Explanation:

The given chemical equation is:

2NO(g)+Br_2(g)\rightarrow 2NOBr(g)

The value of equilibrium constant for the above equation is K_c=1.3\times 10^{-2}.

The value of K_c that means equilibrium lies to the left side. Thus, the equilibrium favors NO and Br_2.

We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

(1) 2NOBr(g)\rightarrow 2NO(g)+Br_2(g)

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{c_1}=\frac{1}{K_c}

K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9

Thus, the value of equilibrium constant for this reaction is, 76.9

(2) NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{c_2}=(\frac{1}{K_c})^{1/2}

K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77

Thus, the value of equilibrium constant for this reaction is, 8.77

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3 years ago
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