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ruslelena [56]
3 years ago
5

A cylinder of argon contains 50 L of Ar at 12.4 atm and 127°C . How many moles of argon are in the cylinder

Chemistry
1 answer:
joja [24]3 years ago
6 0

Answer:

18.9 moles

Explanation:

We have the following data:

V = 50 L

P = 12.4 atm

T= 127°C + 273 = 400 K

R = 0.082 L.atm/K.mol (it is the gas constant)

We use the ideal gas equation to calculate the number of moles n of the gas:

PV = nRT

⇒ n = PV/RT = (12.4 atm x 50 L)/(0.082 L.atm/K.mol x 400 K) = 18.9 mol

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Answer:

<h2>7.58 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 2.01 × 3.77 = 7.5777

We have the final answer as

<h3>7.58 g</h3>

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What is the experimental molar heat of combustion?
IRISSAK [1]

Explanation:

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Use the law of conservation of mass to answer the questions.
irinina [24]

Answer:

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The reactants are A and B. The mass of A is 19 grams and the mass of B is 24 grams. Add the masses.

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This is the mass of the reactants.

The products and C and D. The mass of C is 15 grams. The mass of the products has to equal the mass of the reactants, which is 43 grams. Subtract 15 from 43 to find D's mass.

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laila [671]
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Having 1.6216 moles of KCl ions dissolved in 1000g of water, gives us 1.6216 molar if solution.
Using the freezing point depression constant of water.
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dT = (1.86 C/ molar) (1.6216 m)
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Therefore, it should freeze at - 3.016 Celsius

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3 years ago
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