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8_murik_8 [283]
3 years ago
9

Are predators or their prey more likely to be successful?

Physics
2 answers:
puteri [66]3 years ago
8 0
Predators are more likely to be more successful because they are typically bigger and more powerful than the prey
mihalych1998 [28]3 years ago
3 0
Predator because they are the one’s preying on the animals, the chances of the prey getting away is slim.
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Can someone please help me answer 14 and 15??
ziro4ka [17]
14. The Aurora is an incredible light show caused by collisions between electrically charged particles released from the sun that enter the earth's atmosphere and collide with gases such as oxygen and nitrogen. The lights are seen around the magnetic poles of the northern and southern hemispheres.

15.
About 5.4 billion years from now, the sun will have exhausted all of its hydrogen. The sun's core will get really hot and dense, thus shrinking; however, the outer region of the sun will expand and grow. ... Even if the expanding dying sun doesn't reach Earth, the sun's high temperatures will completely burn the planet.
7 0
4 years ago
You need to design a banked curve at the new circular Super 100 Raceway. The radius of the track is 800 m and cars typically tra
uysha [10]

Answer:

33.1^{\circ}

Explanation:

Let's start by writing the equations of the forces along the two directions:

- Vertical:

N cos \theta = mg

where

N is the normal reaction

\theta is the angle between the road and the horizontal

(mg) is the weight of the car, with m being its mass and g the acceleration of gravity

- Horizontal:

N sin\theta = m \frac{v^2}{r}

where

v is the speed of the car

r is the radius of the turn

Dividing the 2nd equation by the 1st one, we get:

tan \theta = \frac{v^2}{rg}

In this problem:

r = 800 m (radius of the turn)

v=160 mi/h = 71.5 m/s is the speed

g=9.8 m/s^2

Substituting, we find:

\theta= tan^{-1} (\frac{v^2}{rg})=tan^{-1}(\frac{(71.5)^2}{(800)(9.8)})=33.1^{\circ}

8 0
4 years ago
A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.
noname [10]

Answer:

The value is  \rho_s  =  4.026 *10^{-6} \  C/m^2

Explanation:

From the question we are told that

   The radius of the inner conductor  is  r_1 = 1 \ mm =  0.001 \ m

    The radius of the outer conductor is  r_2 = 3 \ mm = 0.003 \  m

    The potential at the outer conductor is  V = 1.5 kV  =  1.5 *10^{3} \  V

Generally the capacitance per length of the capacitor like set up of the two conductors is

      C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}

Here \epsilon_o is the permitivity of free space with value  \epsilon_o =  8.85*10^{-12} C/(V \cdot m)

=>   C= \frac{2 *  3.142  * 8.85*10^{-12}  }{ ln [\frac{0.003}{0.001} ]}

=>   C= 50.6 *10^{-12} \  F/m

Generally given that the potential  of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line  charge density of the outer  conductor is mathematically represented as

      \rho_l  =  C *  V

=>   \rho_d  =  50.6*10^{-12} *  1.5*10^{3}

=>   \rho_d  =  7.59*10^{-8} \  C/m

Generally the surface charge density is mathematically represented as

        \rho_s  =  \frac{\rho_l }{2 \pi * r_2 }    here 2 \pi r = (circumference \ of \ outer \  conductor  )

=>    \rho_s  =  \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }

=>    \rho_s  =  4.026 *10^{-6} \  C/m^2

3 0
3 years ago
Consider the incomplete equation below mc020-1.jpg If this equation was completed, which statement would it best support? Nuclea
vagabundo [1.1K]
<span>Nuclear fission produces elements that are heavier than helium.

The elements that are used in nuclear fission and their products are much heavier than helium.</span>
8 0
3 years ago
Read 2 more answers
One of the solid reactants was treated in a coffee grinder before adding to
Nikitich [7]

Answer:

C. Surface area

Explanation:

The rate of  chemical reaction depends on various factors such as:

  • concentration and pressure
  • nature of reactants
  • temperature
  • surface area
  • presence of catalyst, etc.

Effect of surface area of reactants: the rate of a chemical reaction can be increased by increasing the the area of contact of the reacting substances. This is especially important when one or more of the reactants are solids., because only the particles of the solid that are exposed are able to take part in the reaction at each instant of time. Therefore, the greater the surface area of the solid reactant particles the faster the reaction.

The surface area of solid reactants can be increased by grinding or pelletizing, thus allowing for a greater contact between the reacting particles,

The instance in which one of the solid reactants was treated in a coffee grinder before adding to the reaction container is one way of increasing the surface area of a reactant.

7 0
3 years ago
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