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Katarina [22]
2 years ago
6

Solve for the indicated variable. The first one please!

Mathematics
1 answer:
lions [1.4K]2 years ago
6 0

Answer:

<em>x</em> = <em>y</em> + 6<em>z</em>

Step-by-step explanation:

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Which shows the expression below in simplified form? (5 × 10^5) × (7 × 10^-5)
katrin [286]

Answer:1,750,000,000

Step-by-step explanation:first the number ten to the fifth power is 1,000,000 then times five is 5,000,000. Then the number ten to the negative fifth power is 50 times seven is 350. 5,000,000 times 350 is 1,750,000,000

4 0
3 years ago
Can someone help me with this?
faltersainse [42]

Answer:

I think it's graph 2 hope that helps

7 0
2 years ago
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Write an equation from a real life situation
bogdanovich [222]

Answer:

1. C=35m?

2.C=700 or $700

Step-by-step explanation:

1. Total Cost= Rate x Number of Months

2. C=35m

Cost=rate x number of months

C=35(20)

C=700 or Total Cost=$700

6 0
2 years ago
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Please help me this is important to my grade
defon

Answer:

C. x = 6

Step-by-step explanation:

2*6 + 4 = 16

6 0
3 years ago
Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i
kolezko [41]

Answer:

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

Step-by-step explanation:

Data given and notation

Data:    801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=811 represent the sample mean  

s=19.647 represent the standard deviation for the sample

n=5 sample size  

\mu_o =750 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:  

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

What do you conclude?  

Compute the p-value  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

4 0
3 years ago
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