M(C)=73.5 g
m(H)=4.20 g
m(Cl)=72.3 g
mass of compound
m=m(C)+m(H)+m(Cl)
m=73.5+4.20+72.3=150 g
w(H)=100m(H)/m
w(H)=100*4.20/150=2.8%
w(Cl)=100m(Cl)/m
w(Cl)=100*72.3/150=48.2%
w(C)=100-w(H)-w(Cl)
w(C)=100-2.8-48.2=49.0%
Answer:
The compound was a 3° alcohol.
Explanation:
The chromic acid test is positive for 1° and 2° alcohols, but negative for 3° alcohols.
The answer to this would be false.
