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Zanzabum
3 years ago
11

What is the answers to these questions?

Chemistry
1 answer:
serious [3.7K]3 years ago
4 0

2. B

3. B

4. A

5. C

6. B

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Express the quantity 556.2 x 10^-12 in each units<br> A.) ms<br> B.) ns<br> C.) ps<br> D.) fs
zavuch27 [327]
The answer:
we should know the meaning of each abbreviation:
ms means  millisecond, its value is 10^-3 s 
ns means  means  nanosecond,   its value is 10^-9 s
ps means  picosecond, its value is 10^-12 s
fs means  femtosecond, its value is 1x 10^15 s

<span>Expressions of the quantity 556.2 x 10^-12 are</span>
556.2 x 10^-12 =556.2 ps
556.2 x 10^-12 =556.2 x 10^-9 x 10^-3= 556.2 x 10^-9 ms
556.2 x 10^-12 = 556.2 x 10^-3 x 10^-9 = 556.2 x 10^-3 ns
556.2 x 10^-12 = 556.2 x 10^- 27 x 10^15 = 556.2 x 10^- 27 fs
6 0
3 years ago
How many moles of nitrogen, N, are in 62.0 g of nitrous oxide, N2O?​
SSSSS [86.1K]
Answer- the estimated number is 4 moles but it actually is 3.86 moles
Explanation
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<33
8 0
2 years ago
What kind of bond is formed between a metal and a nonmetal? Explain your answer.
shusha [124]

Answer:

NVIDIA GeForce RTX 3080 10GB GDDR6X PCI Express 4.0 Graphics Card

Explanation:

5 0
3 years ago
Read 2 more answers
What volume of Co2 (carbon (iv) oxide)
hram777 [196]

Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

7 0
4 years ago
A volume of 25.36 ± 0.05 mL 25.36±0.05 mL of HNO 3 HNO3 solution was required for complete reaction with 0.8311 ± 0.0007 g 0.831
Sholpan [36]

Answer:

MOLARITY= 0.3092mol/l

ABSOLUTE UNCERTAINTY= 0.000873

Explanation:

The equation of reaction is

2HNO3 + Na2CO3 ⟶ 2NaNO3 + H2O + CO2.

QUESTION1: CALCULATION FOR MOLARITY;

Molarity= gram mole of solute ÷ liters of solution

Where;

Mole of solute= mass ÷ molar mass

Therefore;

Mole of solute= 0.8311g ÷ 105.988g/mol= 0.0078515mol

MOLARITY= 0.0078415mol ÷ 25.36ml = 0.0003092mol/ml = 0.3092mol/l

This is the Molarity of the solution

QUESTION2: CALCULATION FOR ABSOLUTE UNCERTAINTY;

Uncertainty (u) =√([0.05 ÷ 25.36]^2 + [0.001 ÷ 105.988]^2 + [0.0007 ÷ 0.8311]^2) × Molarity

Solving brackets gives

(0.00197161+0.00000943503+0.00084226) ×Molarity

Adding up gives

0.002823×Molarity

Therefore;

ABSOLUTE UNCERTAINTY= 0.002823×0.3092= 0.000873

5 0
3 years ago
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