Answer:
1.2 x 10>24 (2.0)(6.022 x 10>23)
Explanation:
How many formula units are in 2.0 moles of Fe(NO3)2?
Answer:
2.51 x 1023 atoms C
Explanation:
MW C = 12.011
5g x (1mol/12.011g) =0.416 mol
0.416 mol x (6.022x10^23) = 2.51 x 1023 atoms C
Answer: The moles of gas present in the cylinder is 0.34 moles.
Explanation:
Given: 
= 2.7 atm, 
= 3.1 L, 
= 300 K
= ?, 
= 9.4 L, 
= 610 K
Formula used to calculate the final temperature is as follows.
Substitute the values into above formula as follows.
Now, moles present upon heating the cylinder are as follows.
Thus, we can conclude that moles of gas present in the cylinder is 0.34 moles.
Answer:
Mass = 14.0 g
Explanation:
Given data:
Mass of mercury nitrate = 22.17 g
Mass of mercury formed = ?
Solution:
Chemical equation:
Hg(NO₃)₂ + 2K → 2KNO₃ + Hg
Number of moles of mercury nitrate:
Number of moles = mass/molar mass
Number of moles = 22.17 g / 324.6 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of Hg(NO₃)₂ and mercury.
Hg(NO₃)₂ : Hg
1 : 1
0.07 : 0.07
Mass of mercury:
Mass = number of moles × molar mass
Mass = 0.07 mol × 200.6 g/mol
Mass = 14.0 g
Answer:
D) she is confident and has already made plans
