Let the equal sides of the isosceles Δ ABC be x.
Given that the perimeter of Δ ABC = 50m.
Therefore, 2x + AC = 50 --- (1)
It is also given that the perimeter of Δ ABD = 40m.
Therefore, x + BD + AD = 40
BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.
So AD = CD.
Or, AD = AC
Therefore,
Multiply both sides by 2.
2x + 2BD + AC = 80
From (1), 2x + AC = 50.
Therefore, 2BD + 50 = 80
2BD = 80 - 50
2BD = 30
BD = 15m.
The lengths of sides of second triangle are:
10cm, 18cm and 22cm
Step-by-step explanation:
Given
Ratios of sides of triangle=> 1:2
Given sides of a triangle:
5cm,9cm and 11 cm
The ratio 1:2 means that for each 1 cm in first triangle, there are 2 cms in seconds triangle. This simply means that the sides of the second triangle are double of the first triangle.
So,
The sides of the second triangle are:
Hence,
The lengths of sides of second triangle are:
10cm, 18cm and 22cm
Keywords: Triangles, ratios
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