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malfutka [58]
3 years ago
7

6. Explain Why does coating surfaces with oil reduce friction between the surfaces?

Physics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

Explanation:

Coating surfaces with oil can reduce friction because it makes the surface smoother

Akimi4 [234]3 years ago
7 0

Answer:

hope this helps

Explanation:

Coating surfaces with oil reduce friction between the surfaces because it is like when lubricating a machine, it makes it run or it makes it become smoother.

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Jasper made a list of the properties of electromagnetic waves. Identify the mistake in the list. Electromagnetic Wave Properties
Nata [24]

Answer:

Statement 2 is wrong

Explanation:

To check the statements in this exercise, let's describe the main properties of electromagnetic waves. Let's describe the characteristics

* they are transverse waves

* formed by the oscillations of the electric and magnetic fields

* the speed of the wave is the speed of light

with these concepts let's review the final statements

1) True. Formed by the oscillation of the two fields

2) False. They are transverse waves

3) True. Can travel by vacuum as they are supported by oscillations of the electric and magnetic fields

4) True. They all have the same speed of light

Statement 2 is wrong

6 0
4 years ago
The thermal conductivity of a cement is 0.168 British thermal units per foot hour degree Fahrenheit ​[BTU divided by (ft h Super
Sliva [168]

Answer:

thermal conductivity =  0.2906 W/m.K

Explanation:

thermal conductivity = 0.168 BTU/h.ft⁰F

1 BTU/h.ft⁰F = 1.7295772056 W/m.k

0.168 BTU/h.ft⁰F = 0.168 * 1.7295772056 W/m.k

0.168 BTU/h.ft⁰F = 0.2906 W/m.k

5 0
4 years ago
¿Cuál es la velocidad del sonido en el aíre a -25°C?
Svetradugi [14.3K]

La velocidad del sonido en el aire (a una temperatura de 20 ºC) es de 343 m/s. La ecuación creada por Newton y posteriormente modificada por Laplace que permite obtener la velocidad del sonido en el aire teniendo en cuenta la variable de la temperatura es "331+(0,6 x Temperatura)".

               

8 0
3 years ago
AEROSPACE On the Moon, a falling object falls just 2.65 feet in the first second after being dropped. Each second it falls 5.3 f
aniked [119]

Answer:

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

Explanation:

This scenario can be represented by an arithmetic progression AP.

nth term = a + nd

Where a is the first term given as 2.63 ft.

d is the common difference and is given as 5.3ft.

n is the particular second/time.

To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.

d = nth sum = (n/2)(2a+(n-1)d)

Where n = 10 seconds

a = 2.65 ft

d = 5.3 ft

Substituting the values we have;

d = (10/2)(2×2.65 + (10-1)5.3)

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

4 0
3 years ago
Read 2 more answers
The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t
mel-nik [20]

Answer:

It will take 0.0611 sec for nerve signal to travel 1.1 m

Explanation:

We have given the nerve cell connecting the spinal card to feet is 1.1 m long

So length d = 1.1 m

And speed of the nerve impulse v = 18 m/sec

We have to find the time for nerve signal to travel that distance

Speed of the nerve signal is given by v=\frac{d}{t}

So t=\frac{d}{v}=\frac{1.1}{18}=0.0611sec

So it will take 0.0611 sec for nerve signal to travel 1.1 m

5 0
3 years ago
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