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3 years ago

6. Explain Why does coating surfaces with oil reduce friction between the surfaces?

Physics

2 answers:

natali 33 [55]3 years ago

8 0

Answer:

Explanation:

Coating surfaces with oil can reduce friction because it makes the surface smoother

Akimi4 [234]3 years ago

7 0

Answer:

hope this helps

Explanation:

Coating surfaces with oil reduce friction between the surfaces because it is like when lubricating a machine, it makes it run or it makes it become smoother.

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The speed of light in vacuum is exactly 299,792,458 m/s. A beam of light has a wavelength of 651 nm in vacuum. This light propag

sukhopar [10]

Answer:

$v=2.58\times10^8m/s$

Explanation:

The index of refraction is equal to the speed of light c in vacuum divided by its speed v in a substance, or $n=\frac{c}{v}$ . For our case we want to use $v=\frac{c}{n}$ , which for our values is equal to:

$v=\frac{c}{n}=\frac{299792458m/s}{1.16}=258441774.138m/s$

Which we will express with 3 significant figures (since a product or quotient must contain the same number of significant figures as the measurement with the <em>least</em> number of significant figures):

$v=2.58\times10^8m/s$

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4 years ago

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MariettaO [177]

Answer:

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3 years ago

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how long will it take you to travel from rustburg hign school to watch the Devils beat the brookville bees if you live 20 miles

tresset_1 [31]

(20 miles) x ( 1/45 hour/mile) =

(20/45) (hour) = <em>

4/9 hour = </em>26 minutes 40 seconds

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3 years ago

PLEASE HELP I NEED IT RIGHT NOW

morpeh [17]

The answer should be B :)

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3 years ago

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What is the approximate size of the smallest object on the Earth that astronauts can resolve by eye when they are orbiting 250 k

sesenic [268]

Answer:

the approximate size of the smallest object on the Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth is y = 31.495 m

Explanation:

Using Rayleigh criterion for the limiting angle of resolution of an eye

$\theta = \frac{1.22\lambda }{D } \\ \\ \theta = \frac{1.22*506 *10^{-9} }{4.90*10^{-3}m}$

$\theta = 1.2598*10^{-4}$ rad

$\theta = 125.98*10^{-6} \ rad$

Thus; the separation between the two sources is expressed as:

$\theta = \frac{y}{L} \\ \\ y = L \theta \\ \\ y = (250*10^3 )(125.98*10^{-6} \ rad) \\ \\ y = 31.495 \ m$

Thus; the approximate size of the smallest object on the Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth is y = 31.495 m

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3 years ago