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GaryK [48]
3 years ago
12

A mass weighing 22 lb stretches a spring 4.5 in. The mass is also attached to a damper with Y coefficient . Determine the value

of Y for which the system is critically damped. Assume that g=32 ft/s2. Round your answer to three decimal places.
Engineering
1 answer:
Dominik [7]3 years ago
5 0

Answer:

Cc= 12.7 lb.sec/ft

Explanation:

Given that

m = 22 lb

g= 32 ft/s²

m = \dfrac{22}{32}=0.6875\ s^2/ft

x= 4.5 in

1 in = 0.083 ft

x= 0.375 ft

Spring constant ,K

K=\dfrac{m}{x}=\dfrac{22}{0.375}

K= 58.66  lb/ft

The damper coefficient for critically damped system

C_c=2\sqrt{mK}

C_c=2\sqrt{0.6875\times 58.66}

Cc= 12.7 lb.sec/ft

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A cylindrical bar of metal having a diameter of 17.8 mm and a length of 196 mm is deformed elastically in tension with a force o
ExtremeBDS [4]

Answer:

A) ΔL = 0.544 mm

B) Δd = -0.0168 mm

Explanation:

We are given;

Elastic modulus; E = 67.1 GPa = 67.1 × 10^(9) Pa

Force; F = 46400 N

Diameter; d = 17.8 mm = 17.8 × 10^(-3) m

Radius; r = d/2 = 17.8/2 = 8.9 mm = 8.9 × 10^(-3) m

Length; L = 196 mm = 0.196 m

Poisson ratio; ν = 0.34

A) We know that formula for elastic modulus is;

E = σ/ε

Where;

σ = F/A

ε = ΔL/L

Thus;

E = (FL/ΔL•A)

ΔL is change in length. Making it the subject of the formula, we have;

ΔL = FL/AE

Now, A = πr²

A = π × (8.9 × 10^(-3))²

ΔL = [(0.196 × 46400)/(π × (8.9 × 10^(-3))² × 67.1 × 10^(9)]

ΔL = 0.544 × 10^(-3) m

ΔL = 0.544 mm

B) formula for Poisson ratio is given as;

ν = -ε_x/ε_z

Where;

ε_x is transverse strain = Δd/d

ε_z is longitudinal strain = ΔL/L

Thus;

ν = -Δd•L/d•ΔL

Making Δd the subject, we have;

Δd = -νdΔL/L

Δd = -(0.34 × 17.8 × 10^(-3) × 0.544 × 10^(-3))/0.196

Δd = -0.0168 × 10^(-3) m = -0.0168 mm

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The reason why many sustainable fishing and forestry practice depend on the actions of consumers like me is:

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At a given point in a supersonic wind tunnel, the pressure and temperature are 5×104 N/m2 and 200 K, respectively. The total pre
Ne4ueva [31]

Answer:

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Total temperature To = 528.524K

Explanation:

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(0.3 * 10^2)^(1/3.5) = 1 + 0.2M^2

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3 years ago
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