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OleMash [197]
3 years ago
9

Help me please show the work

Chemistry
1 answer:
Feliz [49]3 years ago
3 0

2 => 6 meters = 600cm

3 => 70 quarts = 17.5 gallon

50 inches = 1.5 meters

2,000 grains = 4.57 ounces

7 tablespoons = 0.027344 gal

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An iron storage tank is placed in the ocean with no cathodic protection. a. What is the electrolyte in this reaction? b. As the
MariettaO [177]

Answer:

Iron is being oxidized at the anode and water is acting as the electrolyte.

Explanation:

When iron is exposed to oxygen and water , the rusting of iron takes place.

<u>The reaction taking place at anode : Oxidation of iron.</u>

{anode:}\;\text{Fe}(s)\;{\longrightarrow}\;\text{Fe}^{2+}(aq)\;+\;2\text{e}^{-}

The reaction taking place at cathode : Reduction of oxygen in the air.

{cathode:}\;\text{O}_2(g)\;+\;4\text{H}^{+}(aq)\;+\;4\text{e}^{-}\;{\longrightarrow}\;2\text{H}_2\text{O}(l)  

The overall reaction:

{overall:}\;2\text{Fe}(s)\;+\;\text{O}_2(g)\;+\;4\text{H}^{+}(aq)\;{\longrightarrow}\;2\text{Fe}^{2+}(aq)\;+\;2\text{H}_2\text{O}(l)

The rust that is hydrated iron(III) oxide can form iron(II) ions which can react further with oxygen.

4\text{Fe}^{2+}(aq)\;+\;\text{O}_2(g)\;+\;(4\;+\;2x)\;\text{H}_2\text{O}(l)\;{\longrightarrow}\;2\text{Fe}_2\text{O}_3{\cdot}x\text{H}_2\text{O}(s)\;+\;8\text{H}^{+}(aq)

Thus, from the above reactions ,

Iron is being oxidized at the anode and water is acting as the electrolyte.

3 0
4 years ago
The titration of a 20.0-mL sample of an H2SO4 solution of unknown concentration requires 22.60 mL of a 0.158 M KOH solution to r
soldier1979 [14.2K]

Answer:

M₁ = 0.178 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,  

M₁ = concentration of acid ,  

V₁ = volume of acid,

M₂ = concentration of base ,

V₂ = volume of base,

from , the question ,  

M₁ = ?

V₁ = 20.0 mL

M₂ = 0.158 M

V₂ = 22.60 mL

Using the above formula , the molarity of the acid , can be calculated as ,  

M₁V₁ = M₂V₂

M₁ * 20.0 mL = 0.158 M * 22.60 mL

M₁ = 0.178 M

5 0
4 years ago
Which one of the following chemicals does the body generate during regular exercise?
Slav-nsk [51]
B. Endorphins are released during exercise
7 0
4 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
natali 33 [55]

Answer:

a) rate law =  k[HgCl₂][C₂O₄²⁻]²

b) K = 8.67 * 10⁻⁵M⁻²s⁻¹

c) rate = 2.55 * 10⁻⁵Ms⁻¹

Explanation:

a) From the given data, rate law is given as: rate = k[HgCl₂]ᵃ[C₂O₄²⁻]ᵇ

Note: Further calculations and explanations are found in the attachment below

6 0
3 years ago
In any electromagnetic wave, A) both the energy and the wave travel in the same direction. B) only the oscillating electric fiel
KengaRu [80]
<span>I believe the answer is letter c. haf energy is carried by the electric field hand half is carried by a magnetic field. the movements are in travelling in a perpendicular movement, a kind of x and y axis that creates oscillation producing electric fields. The effect can make magnet out of electricity.</span>
3 0
4 years ago
Read 2 more answers
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