Answer:
A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.
What is the specific heat of the substance?
If it is one of the substances found in Table 8.1.1, what is its likely identity?
The correct answer for the question that is being presented above is this one: "They are both balanced chemical equations." The <span>statement that is correct about the chemical reaction is that both chemical reaction are balanced chemical equations.</span>
Al2(SO4)3 would be the formula.
Freezing rain is the term given to the precipitation of the rain sustained at temperatures below freezing by the ambient air mass, which results in freezing on encountering with the surfaces. Freezing rain is formed completely of liquid droplets, unlike sleet, ice pellets, or hail.
The freezing rain falls and solidifies on a wire fence as the rain is changing from a liquid to a solid state by withdrawing thermal energy, ultimately resulting in freezing.
Answer:
248.4 mL
Explanation:
Erlenmeyer = 78.649 g
Erlenmeyer + Water = 327.039 g
Water = (Erlenmeyer + Water) - Erlenmeyer
Water = 327.039 - 78.649
Water = 248.4 g
if the density of water is 1 g/mL, we can say that each mL of water weigh 1 g, so we have 248.4 mL of water in the Erlenmeyer Flask.
