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Anna [14]
2 years ago
8

What is the ph of a solution that has a [h ] = 0. 0039 m?

Chemistry
1 answer:
Sedbober [7]2 years ago
6 0

The pH of a solution that has a H⁺ ion concentration is 0.0039M is 2.4.

<h3>What is pH?</h3>

pH of any solution gives idea about the acidity or basicity of solution and it will be calculated as:

pH = -log[H⁺]

Given that, concentration of H⁺ ion = 0.0039 M

On putting tis value in pH equation, we get

pH = -log(0.0039)

pH = -(-2.4) = 2.4

Hence required value of pH is 2.4.

To know more about pH, visit the below link:
brainly.com/question/24595796

#SPJ1

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A student wants to prepare 1.00 L of a 1.00 M solution of NaOH (molar mass 40.00 g/mol). If solid NaOH is available, how would t
Serga [27]

Explanation:

1)

Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}

Mass of NaOH = m

MOlar mass of NaOH = 40 g/mol

Volume of NaOH solution = 1.00 L

Molarity of the solution= 1.00 M

1.00 M=\frac{m}{40 g/mol\times 1.00 L}

m=1.00 M\times 40 g/mol\times 1.00 L = 40. g

A student can prepare the solution by dissolving the 40. grams of NaOH in is small volume of water and making that whole volume of solution to volume of 1 L.

Upto two significant figures mass should be determined.

2)

M_1V_1=M_2V_2 (dilution equation)

Molarity of the NaOH solution = M_1=2.00 M

Volume of the solution = V_1=?

Molarity of the NaOH solution after dilution = M_2=1.00 M

Volume of NaOH solution after dilution= V_2=1 L

M_1V_1=M_2V_2

V_1=\frac{1.00 M\times 1.00 L}{2.00 M}=0.500 L

A student can prepare NaOH solution of 1.00 M by diluting the 0.500 L of 2.00 M solution of NaOH with water to 1.00 L volume.

Upto three significant figures volume should be determined.

8 0
3 years ago
What is H20 and oxygen
olga2289 [7]
H2O means water, which is made of two hydrogen and one oxygen atoms.
Oxygen is a gas that your body needs to function. Oxygen comes from the air.
4 0
3 years ago
Read 2 more answers
Which statement describes the bonds in iron sulfate, FeSO4?
Feliz [49]

___

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Elements form bonds to increase their stability. The main types of bonds are:

  • Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
  • Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
  • Covalent bonds: they are formed between nonmetals, which share electrons.

Regarding the bonds in FesO₄:

  • Fe is a metal and S a nonmetal, thus they will form ionic bonds.
  • S and O are both nonmetals, thus they will form covalent bonds.

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Learn more: brainly.com/question/23882847

5 0
2 years ago
Which of the following is an incorrect way of rearranging the density formula:
goldenfox [79]
We know that density = mass /volume
so
mass=volume*density
volume=mass/density
so c is wrong
5 0
3 years ago
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Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3
Goryan [66]

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Now put all the given values in the formula of molality, we get

0.038M=\frac{n}{0.278L}

n=0.0105mol  

mass of  Fe_2(SO_4)_3 = moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g

Thus 4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

3 0
3 years ago
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