Based on the electron configuration of the two

What is e cell (in units of volts) for a galvanic cell constructed from barium and manganese electrodes?

gulaghasi [49]

Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.

Explanation:

When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:

Mn2+(aq) + 2e-⟶ Mn(s) E1 = −1.185

Ba2+(aq) + 2e-⟶ Ba(s) E2 = −2.912

By considering the above two reactions, the standard electrode potential can be calculated.

The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts

What is standard electrode potential?

Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.

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3 0

2 years ago

Use the chemical equation below to determine how many moles of ammonia

anzhelika [568]

Answer:

If we assume that there will be enough Hydrogen for the reaction to occur, then there will be 8 moles of NH

Explanation:

The balanced equation will look like this:

4N2 + 4H2 -> 8NH

6 0

3 years ago

Pls help! no explanation needed

NNADVOKAT [17]

Answer:

Option 3.

LiOH(aq) + HNO₃(aq) —> LiNO₃(aq) + H₂O(l)

Explanation:

To know which option is correct, we must have an ideal of what is acid–base neutralization.

Neutralization is a reaction involving an acid and a base which produces salt and water only.

With the above information, we can easily detect the equation describing acid-base neutralization reaction by considering the products of each reaction to see the one that has water as part of the products.

From the question given above, only the 3rd equation gas water as part of the products i.e

LiOH(aq) + HNO₃(aq) —> LiNO₃(aq) + H₂O(l)

Hence, equation 3 is an acid-base neutralization reaction

4 0

3 years ago

DO NOT COMMENT IF YOUR NOT GOING TO HELP ITS REALLY ANNOYING :/

blondinia [14]

Answer:

50 mL; 7

Explanation:

By looking at the graph, the boundary point where the solution turns from acidic to basic appears at approximately 50 mL.

Because this is a titration between a strong acid and strong base, the pH of the equivalence point is always 7 (aka neutral).

8 0

3 years ago

Read the given equation. 2Na + 2H2O ? 2NaOH + H2 During a laboratory experiment, a certain quantity of sodium metal reacted with

emmasim [6.3K]

Answer:

The number of moles of Na metal that used initially = 0.70 mol.

The quantity of Na metal used initially to produce 7.80 of H₂ gas = 16.02 g.

Explanation:

It is a stichiometry problem.

2Na + 2H₂O → 2NaOH + H₂,

The balanced equation shows that 2.0 moles of Na metal react with 2.0 moles of water to produce 2.0 moles of NaOH and 1.0 mole of H₂,

Firstly, we need to convert the volume of H₂ (7.80 L) produced to no. of moles (n) using the ideal gas law: PV = nRT,

where, P is the pressure of the gas in atm (P at STP = 1.0 atm),

V is the volume of the gas in L (V = 7.80 L),

n is the number of moles in mole,

R is the general gas constant (R = 0.082 L.atm/mol),

T is the temperature of the gas in K (T at STP = 0.0 °C + 273 = 273.0 K).

∴ The number of moles of H₂ gas (n) = PV / RT = [(1.0 atm)(7.80 L)] / [(0.082 L.atm/mol.K)(273.0 K)] = 0.35 mol.

Using cross multiplication:

2.0 moles of Na will produce → 1.0 mole of H₂, from the stichiometrey.

??? moles of Na will produce → 0.35 mole of H₂.

∴ The number of moles of Na metal that used initially = (2.0 mol)(0.35 mol) / (1.0 mol) = 0.70 mol.

Now, we can get the quantity of Na metal using the relation:

∴ mass = n x molar mass = (0.70 mol)(22.989 g/mol) = 16.02 g.

6 0

3 years ago