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3 years ago

What is the percent by mass of potassium in K3Fe(CN)6?

Chemistry

1 answer:

SSSSS [86.1K]3 years ago

6 0

Answer:

Mass percent composition of K = mass contribution of K/molecular mass of K3Fe(CN)6 x 100% Mass percent composition of K = 117.30 g/mol/329.27 g/mol x 100% Mass percent composition of K = 0.3562 x 100% Mass percent composition of K = 35.62%

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A piece of charcoal is found to contain

Naddika [18.5K]

Answer: The tree died 9709.46 years before.

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = $\frac{30}{100}\times 100=30$

a) to find rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$k=\frac{0.693}{5600years}=1.24\times 10^{-4}years^{-1}$

b) to know the age

$t=\frac{2.303}{1.24\times 10^{-4}}\log\frac{100}{30}$

$t=9709.46years$

The tree died 9709.46 years before.

8 0

3 years ago

What volume of 3.00 MM HClHCl in liters is needed to react completely (with nothing left over) with 0.750 LL of 0.500 MM Na2CO3N

AlladinOne [14]

Answer: The volume of HCl needed is 0.250 L

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

For sodium carbonate:

Molarity of sodium carbonate solution = 0.500 M

Volume of solution = 0.750 L

Putting values in above equation, we get:

$0.500M=\frac{\text{Moles of sodium carbonate}}{0.750}\\\\\text{Moles of sodium carbonate}=(0.500mol/L\times 0.750L)=0.375mol$

The chemical equation for the reaction of sodium carbonate and HCl follows:

$Na_2CO_3+2HCl\rightarrow 2NaCl+H_2CO_3$

By Stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 2 moles of HCl

So, 0.375 moles of sodium carbonate will react with = $\frac{2}{1}\times 0.375=0.750mol$ of HCl

Now, calculating the volume of HCl by using equation 1:

Moles of HCl = 0.750 moles

Molarity of HCl = 3.00 M

Putting values in equation 1, we get:

$3.00M=\frac{0.750mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.750mol}{3.00mol/L}=0.250L$

Hence, the volume of HCl needed is 0.250 L

8 0

3 years ago

Group 17 elements (for example, chlorine) in the periodic table are known as

BaLLatris [955]

Explanation:

The answer is halogens

Halogens are reactive non metallic elements that form strongly acidic compounds with Hydrogen to form simple salts

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3 years ago

What mass of hydrogen chloride is formed when 1 mole of hydrogen reacts with 1 mole of chlorine?

Vadim26 [7]

The balanced reaction that describes the reaction between hydrogen and chlorine to produce hydrogen chloride is expressed H2 + Cl2 = 2HCl. Hence for every mole hydrogen chloride produced, there is 1 mole of hydrogen and chlorine needed. When 1 mole each of the reactants are used, there is 72.9 grams of HCl produced. We multiply 2 with the molar mass of HCl.

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4 years ago

Complete the table by classifying each property as either a physical or chemical property

Advocard [28]

Where is the table? I dont know what to classify

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3 years ago