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3 years ago

An unconformity between two sedimentary layers is classified as a disconformity. true or false

Physics

1 answer:

Strike441 [17]3 years ago

3 0

Answer:

hii there

The correct answer is True

Explanation:

Hope it helps

have a nice day :)

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A dog walks 100m at a bearing of 175 degrees. a) How far did it walk East?

LUCKY_DIMON [66]

1 kilometer

Explanation:

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3 years ago

When an electric current is passed through water during the process of electrolysis, two gases are formed. One gas has a boiling

konstantin123 [22]

The chemical change occurred. Electrolysis is used by scientists to make chemical reactions that wouldnt normaly spontaniously ocur. In this case we are getting new gases from water molecul which is change in structure of elements ( we are getting new moleculs)

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3 years ago

In an experiment, the explanation of the expected outcome, based on research, is the _______________.

vladimir1956 [14]

C. Hypothesis
The hypothesis is presented as an explanation of the observed results.

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3 years ago

Which car has the most kinetic energy? <br><br> (PLEASE HELP NEED ANSWER ASAP)

Hatshy [7]

Kinetic energy = 1/2 mv²

so, you will have to do it for every single one of them if you want steps.

Kinetic Energy = For A, 202500J

For B, 90000J

For C, 168750J

For D, 75000J

From the above we an say that kinetic energy is highest in option A.

In case, there are no steps needed, just by the values we are able to understand the answer as in Option A, eventhough the mass is the same, higher the velocity or speed, higher the kinetic energy

6 0

3 years ago

A long, hollow wire with inner radius a and outer radius b carries a uniform current density J. What is the magnetic field as a

sveta [45]

Answer:

The magnetic field in the region a < r < b is $B=\frac{u_{0}I(r^{2}-a^{2}) }{2\pi r(b^{2}-a^{2}) }$

Explanation:

If we have the a < r < b. The formula of current is:

$J=\frac{I_{total} }{A}$

Where:

A = area enclosed by the loop.

Itotal = total current in loop.

$J=\frac{I}{\pi b^{2}-\pi a^{2} }$

$I_{enclosed} =JA_{enclosed}$

$I_{enclosed} =\frac{I(\pi r^{2}- \pi a^{2})}{\pi b^{2}-\pi a^{2} }$

If we have the Ampere`s law:

$\int\limits^a_b {B} \, ds =u_{0} I_{enclosed} \\2B\pi r=u_{0} (\frac{I(\pi r^{2}-\pi ^{2} }{\pi ^{2}-\pi a^{2} } )\\B=\frac{u_{0}I(r^{2}-a^{2}) }{2\pi r(b^{2}-a^{2}) }$

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3 years ago