With the given components above, the chemical reaction required to solve the problem is <span>H2C2O4*2H2O + 2 NaOH = 4 H2O + Na2C2O<span>4 where 1 mole of diprotic acid needs 2 moles of NaOH to complete the reaction.In this case, given </span></span><span>0.4500 M NaoH and 0.02 L of it, the moles diprotic acid needed is 0.0045 moles. This is equivalent to 0.351 grams.</span>
The three include Solids, Liquids, and Gases
Molar mass MgCO3 => 84.31 g/mol
1 mole MgCO3 ----------- 84.31 g
1.5 moles MgCO3-------- ??
1.5 x 84.31 / 1 => 126.465 g
Answer:
a)
b)
hours
Explanation:
Given
Surface Area (S) of 250 grams of powder sample 
square meter.
square centimeter
grams/minute
mg per second
gram per cubic meter 
mg/ml
a)
cm /sec
b) Time taken
Time taken to sink
Time in hours
hours
