Elements that have six electrons in the highest-energy p sublevel in their ground state are called the noble gases or inert gases. The six noble gases that occur naturally are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and the radioactive radon (Rn).
Missing question:
<span>(1) C2H5OH (3) C12H22O11
(2) C6H12O6 (4) CH3COOH.
Answer is: 4) CH</span>₃COOH, acetic acid.
In water, acetic acid dissociates on ions, so it can conduct electricity:
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).
When we put
electrodes (cathode and anode) in acetic acid solution, positive and negative
ions migrate to electrodes.<span>
Negative acetate ions go to positive electrode
and gives electrons to electrode.
<span>Positive hydrogen ions go to negative electrode
and gain electrons.</span></span>
Answer: mole
A formula unit represents the simplest ratio of elements in a mole of an ionic compound.
Explanation:
The formula unit, also known as the empirical formula, gives the simplest whole number ratio of the components of the elements in a mole of an ionic compound.
Thus, the formula unit and the molecular formula of a compound can be the same.
For example: Glucose with C6H12O6 will have a formula unit of CH2O. Thus, the simplest ratio of carbon, hydrogen and oxygen in glucose is 1:2:1
E because glucose is a very important energy to help an organism
Answer:
The answer to your question is below
Explanation:
For the reaction N2 + 3H2 = 2NH3, if you have 2.00 moles of N2 and 4.00 moles of H2 : a. Identify the limiting reactant. ____________
N2 + 3H2 = 2NH3
1 mol 3 moles 2 moles
Given 2 moles 4 moles
Rule of three for N2
x = (2 x 3) / 1 = 6 mol of H2, it means that is needed 6 moles of H2 and there are only 4, so the limiting reactant is H2
b. How many moles of NH3 can be formed? ____________
rule of three
3 moles of H2 --------------------- 2 moles of NH3
4 moles of H2 --------------------- x
x = (4x2)/3 = 2.7 moles of NH3 are formed
c. How many moles of the excess reactant will remain? _________
x = (4 x 1) / 3 = 1.33
Excess reactant = 2 - 1.33 = 0.67 moles
