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bekas [8.4K]
2 years ago
8

Section C

Mathematics
2 answers:
Murrr4er [49]2 years ago
3 0
•77,035
•61,523
•22,927
•15,369
•78,324
•41,382
•54,180
•53,404
•63,002
•22,852
sergeinik [125]2 years ago
3 0

Answer:

1. 77,035

2. 61,523

3. 22,927

4. 15,369

5. 78,324

6. 41,382

7. 54,180

8. 53,404

9. 63,002

10. 22,852

Step-by-step explanation:

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a. 15 - 20 = -5

b. 15/20 = 3/4

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Below is the data on the percentage of 25- to 34-year-olds in each of the 50 states and the District of Columbia, listed in alph
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Answer:

Step-by-step explanation:

Given the following data:

31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 40.5 37.2 45.3 36.1 45.5 42.3 33.3 30.3 37.2 45.5 54.3 37.2 49.8 32.1 39.3 40.3 44.2 28.4 46.0 47.2 32.8 32.2 38.5 44.5 44.6 40.9 29.5 41.3 35.4

Value ___frequency____relative frequency %

28.4_______1 __________1. 96

28.6_______2__________3.92

29.5_______1___________1.96

30.3_______1___________1.96

31.5_______2___________3.92

32.1_______1____________1.96

32.2_______1___________1.96

32.8_______1___________1.96

32.9_______2___________3.92

33________2___________3.92

33.3_______1___________1.96

35.4_______1___________1.96

35.5_______2___________3.92

36.1________1___________1.96

36.2_______2___________3.92

37.2_______7___________13.73

38.5_______1____________1.96

39.3_______1____________1.96

40.3_______1____________1.96

40.5_______1____________ 1.96

40.9_______1____________1.96

41.3_______1 ____________1.96

42.3______1_____________1.96

43.3______2____________ 3.92

44.2______1 _____________1.96

44.5______1 _____________1.96

44.6_____ 1 ______________1.96

45.3_____1 _______1.96

45.5_____2 ______3.92

45.9_____2 ______3.92

46______1 _______1.96

47.2_____1 _______1.96

49.8_____1 _______1.96

54.3____1________1.96

68.8____2________3.92

Lower outlier = Q1 - (1.5 × IQR)

Upper outlier = Q3 + (1.5 × IQR)

IQR = Interquartile range ;

Q1 = 1/4(n+1)th term

Q3 = 3/4(n+1)th term

IQR = Q3 - Q1

n = number of observations = 51

Q1 = (51 + 1)/4= 52/4 = 13 th term = 33

Q3 = 3(51 + 1) /4 = 156/4 = 39th term = 44.5

IQR = 44.5 - 33 = 11.5

LOWER OUTLIER = 33 - (1.5*11.5) = 33 - 17.25 = entries < 15.75

UPPER OUTLIER = 44.5 + (1.5*11.5) = 44.5 + 17.25 = 61.75

Entries > 61.75

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3 years ago
In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
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