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snow_tiger [21]
3 years ago
7

What is the difference between vector and scalar quantities.give an example of both.​

Physics
2 answers:
inysia [295]3 years ago
8 0

Answer: The difference between vector and scalar quantity are:

<h3>Vector quality </h3>

i) Vectors have both magnitude and direction.

ii) The sum of vectors may be positive, zero or negative.

iii) Vectors are added by the rules of vector algebra.

iv) For example: velocity, acceleration,force , weight etc...

<h3>Scalar quantity </h3>

i) Scalars have only magnitude

ii) The sum of scalars is always positive.

iii) Scalars are added by the rules of simple algebra.

iv) For example: length,time ,volume ,area etc

Zigmanuir [339]3 years ago
5 0
Difference Between a Scalar & Vector Quantity:

A vector quantity has a direction and a magnitude, while a scalar quantity only has magnitude.

Examples:

Scalar quantity include things like speed, time, volume, mass and temperature, while Vector quantities include things like acceleration, velocity, force, momentum and the increase and decrease in temperature.
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A stone of weight 10N falls from the top of a 250m high cliff. a) Calculate how much work is done by the force of gravity in pul
tiny-mole [99]

Answer:

work done = ( force × displacement)

(a)The force acting on the block is it's self weight and displacement is equal to height of the tower.

work done by gravity = (250 × 10) = 2500 joule

(b) The work done by gravity 2500 joule is transferred to the object in the form of it's kinetic energy.

4 0
2 years ago
A rock has a specific gravity of 2.32 and a volume of 8.64 in3 how much does it weigh
lianna [129]

Answer: 3.21 N

Specific\hspace{1mm} gravity = \frac {Density\hspace{1mm}of\hspace{1mm}substance}{Density\hspace{1mm} of \hspace{1mm}water}

\Rightarrow Density \hspace{1mm}of\hspace{1mm}substance= 2.32\times 1000\hspace{1mm} kg/m^3 = 2320\hspace{1mm}kg/m^3\\ Mass =Density\times volume\\ \Rightarrow 2320 \hspace{1mm} kg/m^3\times 8.64 \hspace{1mm}in^3\times \frac {1.64\times10^{-5} m^3}{1\hspace{1mm}in^3}=0.328 kg

For weight, we will multiply by g=9.8 m/s^{-2}

weight= 0.328\times9.8=3.21\hspace{1mm}N

Hence, the rock would weigh 3.21 N.

3 0
3 years ago
The one invention that has made many complex machines possible is the invention of the:
Dafna11 [192]
Hello!

We can point to the invention of the wheel . The wheel  invention made ​​possible the production of hundreds of complex machinery.

Hugs!!
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3 0
4 years ago
Amina has a mass of 48.4kg, what is her weight.please show calculation
Masja [62]

G=m×g

since g=10N,

G=48.4×10

G=484

I hope it's true .d

good luck

6 0
4 years ago
A 4.0 kg circular disk slides in the x- direction on a frictionless horizontal surface with a speed of 5.0 m/s as shown in the a
finlep [7]

Solution :

Let $m_1=m_2=4$ kg

$u_1 = 5$ m/s

Let $v_1$ and $v_2$ are the speeds of the disk $m_1$ and $m_2$  after the collision.

So applying conservation of momentum in the y-direction,

$0=m_1 .v_1_y -m_2 .v_2_y $

$v_1_y = v_2_y$

$v_1 . \sin 60=v_2. \sin 30$

$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$

$v_2=1.732 \times v_1$

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

Now applying conservation of momentum in the x-direction,

$m_1.u_1=m_1.v_1_x+m_2.v_2_x$

$u_1=v_1_x+v_2_x$

$5=v_1. \cos 60 + v_2 . \cos 30$

$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$

$v_1 = 2.50$ m/s

So, $v_2 = 1.732 \times 2.5$

          = 4.33 m/s

Therefore, speed of the disk 2 after collision is 4.33 m/s

5 0
3 years ago
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