What is the difference between vector and scalar quantities.give an example of both.

Physics

2 answers:

inysia [295]3 years ago

8 0

Answer: The difference between vector and scalar quantity are:

<h3>Vector quality </h3>

i) Vectors have both magnitude and direction.

ii) The sum of vectors may be positive, zero or negative.

iii) Vectors are added by the rules of vector algebra.

iv) For example: velocity, acceleration,force , weight etc...

<h3>Scalar quantity </h3>

i) Scalars have only magnitude

ii) The sum of scalars is always positive.

iii) Scalars are added by the rules of simple algebra.

iv) For example: length,time ,volume ,area etc

Zigmanuir [339]3 years ago

5 0

Difference Between a Scalar & Vector Quantity:

A vector quantity has a direction and a magnitude, while a scalar quantity only has magnitude.

Examples:

Scalar quantity include things like speed, time, volume, mass and temperature, while Vector quantities include things like acceleration, velocity, force, momentum and the increase and decrease in temperature.

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Elect the correct answer. Two identical projectiles, A and B, are launched with the same initial velocity, but the angle of laun

allsm [11]

Answer:

A. The range of A and B are equal.

Explanation:

Let u be the initial speed of both the projectile.

The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.

For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,

The speed in the horizontal direction $= u\cos\theta$

and the speed in the vertical direction is $= u\sin\theta$ upward.

For A:

The speed in the horizontal direction $= u\cos75^{\circ}$

and the speed in the vertical direction is $= u\sin75^{\circ}$ upward.

For B:

The speed in the horizontal direction $= u\cos15^{\circ}$

and the speed in the vertical direction is $= u\sin15^{\circ}$ upward.

Let $t_A$ and $t_B$ are the time of flight for projectile A and B respectively.

As the range is the horizontal distance traveled by the projectile, so

The range for the projectile A $= u\cos75^{\circ}\times t_A\cdots(i)$

The range for the projectile B = $u\cos15^{\circ}\times t_B\cdots(ii)$

At the highest point, the vertical velocity is 0.

Bu using the equation of motion $v^2=u^2 +2a s.$

Here, the final velocity v=0, the initial velocity $u = u \sin \theta$ , h= vertical distance up to the highest point, and $a= -g$ (as per sign convention).