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snow_tiger [21]
3 years ago
7

What is the difference between vector and scalar quantities.give an example of both.​

Physics
2 answers:
inysia [295]3 years ago
8 0

Answer: The difference between vector and scalar quantity are:

<h3>Vector quality </h3>

i) Vectors have both magnitude and direction.

ii) The sum of vectors may be positive, zero or negative.

iii) Vectors are added by the rules of vector algebra.

iv) For example: velocity, acceleration,force , weight etc...

<h3>Scalar quantity </h3>

i) Scalars have only magnitude

ii) The sum of scalars is always positive.

iii) Scalars are added by the rules of simple algebra.

iv) For example: length,time ,volume ,area etc

Zigmanuir [339]3 years ago
5 0
Difference Between a Scalar & Vector Quantity:

A vector quantity has a direction and a magnitude, while a scalar quantity only has magnitude.

Examples:

Scalar quantity include things like speed, time, volume, mass and temperature, while Vector quantities include things like acceleration, velocity, force, momentum and the increase and decrease in temperature.
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A toroidal solenoid has 600 turns, cross-sectional area 6.90 cm2, and mean radius 4.30 cm.
Dahasolnce [82]

(a) The coil's self-inductance is 7.26 mH.

(b) The self-induced emf in the coil is 7.26 V

(c) The direction of the induced emf is from b to a.

<h3>Coil's self-inductance</h3>

L = N²μA/I

L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)

L = 7.26 x 10⁻³ H

L = 7.26 mH

<h3>Self-induced emf in the coil</h3>

emf = N(ΔBA)/t

where;

  • B is magnetic field
  • A is area
  • N is number of turns
  • t is time

B = μNI/L

B1 = (4π x 10⁻⁷ x 600 x 5)/0.043

B1 = 0.0876 T

B2 =  (4π x 10⁻⁷ x 600 x 2)/0.043

B2 = 0.035 T

emf = NΔBA/t

emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)

emf = 7.26 V

The direction of the induced emf is always opposite to the direction of the applied current.

Thus, the direction of the induced emf is from b to a.

Learn more about induced emf here: brainly.com/question/13744192

#SPJ1

3 0
2 years ago
Is gravity air resistance?
kolezko [41]

The engineering principles that this project is based upon are gravity and air resistance. Gravity and air resistance are fundamental concepts of many forms of engineering. After we demonstrate the physical principles of gravity and air resistance through various experiments, the children are to pair off into groups of 2 to apply these concepts to an activity. The demonstrations will include dropping a parachute, a small and large feather, and a maple seed and explaining how air resistance affects their movement.


Using only paper towels, paper, scotch tape, scissors and string as construction materials, the children are to brainstorm, design and create a contraption that will make a pencil or a piece of pasta, depending on their age, fall as slowly as possible. This activity is designed for children ages 6-16. The level of difficulty can be adapted with different materials and different falling objects. The older children will be given heavier objects and a limited amount of material.


By participating in this activity, the children will gain a better understanding of how gravity and air resistance affects falling objects. They will have to work cooperatively with team members in order to reach the goal. While each group tests their innovation, the others will compare their ideas to the one that is being tested and learn the strengths and weaknesses of different designs.


As part of a teachers demonstration our group constructed three parachutes with different characteristics out of nylon. One of the parachutes has one large hole in the center of it. Another parachute has several holes throughout. The third parachute has no holes in it. The idea is that the parachute with the most holes will fall the fastest, where as the one without any hole will fall the slowest, and the one with only one hole will fall between the other two. This will demonstrate how the surface area of a parachute causes the air resistance and makes objects fall slowly.


Our activity meets all of the specified requirements. The children are to solve a problem using physical principals that they have learned, thus engaging in an engineering activity. This activity appeals to all types of children; everyone loves to drop things. Components to the kit are safe, durable and do not take up much room. The activity description is very open-ended and so the children are free to design an original contraption anyway they please. The materials are all cheap and easily accessible at home and at school. Given the time it will take for children to brainstorm ideas, design, construct and test a device, it will take the full length of a class period. The whole kit will fit in a plastic storage tub easily because none of the objects in the kit are longer than one foot.

<span>Discovering Gravity & Air ResistanceBy Jason, Allison, and Dave</span><span> <span>If two objects, an elephant and a feather, are dropped off of the side of a building, which would experience a greater force of air resistance during the fall? Which would hit the ground first?<span>  Note: The above graphic requires Flash.</span>If two balls, one made of foam, and one made of metal, are dropped simultaneously from a tall building, which will fall the fastest?</span></span> <span> <span>What's included in the kit:(1) Teachers Manual(3) Demo Parachutes(1) Roll of Paper Towels(1) Pack of Pencils (24)(1) Spool of string(2) Rolls of Scotch Tape(10) Pairs of Safety Scissors(100) Sheets of Paper(1) Box of Paper Clips(1) Box of Pasta(2) Large Feathers(2) Small Feathers(2) Toy Parachutes   </span></span>

7 0
4 years ago
To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105
-Dominant- [34]

Explanation:

LD₁ = 10⁵ mm⁻²

LD₂ = 10⁴mm⁻²

V = 1000 mm³

Distance = (LD)(V)

Distance₁ = (10⁵mm⁻²)(1000mm³) = 10×10⁷mm = 10×10⁴m

Distance₂ = (10⁹mm⁻²)(1000mm³) = 1×10¹² mm = 1×10⁹ m

Conversion to miles:

Distance₁ = 10×10⁴ m / 1609m = 62 miles

Distance₂ = 10×10⁹m / 1609 m = 621,504 miles.

7 0
3 years ago
Read 2 more answers
a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C
Ymorist [56]

Answer:

0.02976°C

Explanation:

Heat Supplied = mcø

ø = 500/(4*4200)

ø = 0.02976 °C

3 0
3 years ago
A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062
galina1969 [7]

Answer:

Force on the proton will be .73\times 10^{-14}N

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light c=3\times 10^8m/sec

So speed of proton v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec

Magnetic field B = 0.00629 T

Charge on proton q=1.6\times 10^{-16}C

Angle between velocity and magnetic field \Theta =137^{\circ}

Force on the proton is equal to F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N

4 0
3 years ago
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