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slega [8]
3 years ago
5

Fter carrying out some tests at a local stream, you discover that the pH in the stream is extremely low. Based on this, you shou

ld tell your friends to A) go home and play Xbox. B) build a raft to raft down the stream. C) swim in and drink the water from the stream. D) not swim in or drink the water from the stream.
Physics
2 answers:
pantera1 [17]3 years ago
6 0

Not swim in the stream or drink its water.

Option: D

<u>Explanation:  </u>

The pH of water is 7, but according to the question, the pH of the local stream is extremely low that means the alkalinity level of the water is very low. This will cause damage to the persons in the water, the pipes in the pool and also the walls of the pool will get damaged by the low pH of water in the pool. The water was extremely low pH will be acidic that means it will be soft and corrosive. It will destroy the metals used in the pool like copper, zinc and lead, so it can easily harm humans too. So I will wisely suggest my friends not to swim or to drink the water from that.

n200080 [17]3 years ago
5 0

Answer:

D) not swim in or drink the water from the stream

Explanation:

Low pH means the water is acidic which is harmful to your skin as it can cause burns and irritations. So any means of contacting with water is not healthy. The damage to the skin happens as in acidic water it has more H+ than in the neutral water and the extra H+ ions can ionize the atoms  which are combined to form different compounds in the skin when in contact.

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Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. Ass
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Answer:

L = 4.711 *10^{-6} kg m2/s

Explanation:

i =\frac{ml^3}{3}

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   =4.5*10^-5

angular velocity

\omega = \frac{2\pi}{60}

             = 0.1047 rad/s

the angular momentum,

L = I\omega

L = 4.5*10^{-5}* 0.1047 rad/s

L = 4.711 *10^{-6} kg m2/s

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3 years ago
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The wavelength of red light is 7 x 10^-7 meter. Express this value in nanometers
3241004551 [841]

  • The wavelength of the red light in "nanometer" is 7× 10^{2}

  • Wavelength is given as : 7×10^{-7} meter

  • 1 nanometer = (10^{-9} meter)

  • Let X= value of the wavelength in nanometer.

1 nanometer  = 10^{-9} meter

X nanometer = 7× 10^{-7}  meter

  • <em>If we Cross multiply</em>

X nanometer = (\frac{     7* 10^{-7} }{  10^{-9} })

X= 7×10^{2} nanometer

Therefore, the wavelength in "nanometer" is 7×10^{2}

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6 0
3 years ago
10. The electron dot diagram for the element Ne would have ​
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Answer:

2,8

Explanation:

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7 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6
lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

I = \frac{P_{avg}}{A}

I = \frac{P_{avg}}{4\pi r^2}

I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m

I = 6.529*10^{-6}W/m^2

The amplitude of electric field at the receiver is

I = \frac{E_{max}^2}{2\mu_0 c}

E_{max}= \sqrt{2I\mu_0 c}

The amplitude of induced emf by this signal between the ends of the receiving antenna is

\epsilon_{max} = E_{max} d

\epsilon_{max} = \sqrt{2I \mu_0 cd}

Here,

I = Current

\mu_0 = Permeability at free space

c = Light speed

d = Distance

Replacing,

\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}

\epsilon_{max} = 0.05434V

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

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It is a battery (the long and short lines represent 2 cells)
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