given:
mass = 5000 kg
u (initial velocity) = 0 m/s
v (final velocity) = 70 m/s
time taken to change velocity = 3600 s
acceleration = v - u / t
a = 70 - 0 / 3600
a = 70 / 3600
a = 0.0194 m/s2 (approx)
given: mass = 5000 kg
acceleration = 0.0194 (found in 1st part)
force = mass * acceleration
f = ma
f = 5000*0.0194 = 97 N
therefore the acceleration will be 0.0194 m/s2
and the force involved in acceleration will be 97 N
Answer:
Explanation:Assume you are lifting an object with mass 20 kg from the ground to a height of 1.5 m. Assume that you are exerting a constant force in the upward direction and that you are moving the object upward with uniform velocity. The net force on the object is zero. The force you are exerting is equal in magnitude and opposite in direction to the force of gravity. As you are lifting the object you are doing work on the object.
Each of those choices has some truth to it, but three of the five choices also include some nonsense.
A. The voltage <em>divides proportionally</em> among all resistors in the circuit.
<em>B. </em> As more resistors are added, the current will decrease. <em>True,</em> because the total resistance will increase.
C. The <em>sum </em>of the voltage drops will be the total voltage in the circuit.
D. The current is the same <em>through</em> all resistors in the circuit.
<em>E.
</em> The equivalent resistance will be greater than the individual resistors. <em>True,</em> because the equivalent resistance is the sum of the individual resistors.
You could make the two rubbing thingers come closer together.
