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kupik [55]
3 years ago
11

In the laboratory you dilute 5.32 mL of a concentrated 6.00 M perchloric acid solution to a total volume of 100 mL. What is the

concentration of the dilute solution
Chemistry
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

0.3192 M

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5.32 mL Molarity of stock solution (M1) = 6 M

Volume of diluted solution (V2) = 100 mL

Molarity of diluted solution (M2) =?

We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:

M1V1 = M2V2

6 × 5.32 = M2 ×100

31.92 = M2 × 100

Divide both side by 100

M2 = 31.92 / 100

M2 = 0.3192 M

Therefore, the molarity of the diluted solution is 0.3192 M.

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A. dose
a dose is an amount, a response is an action, and pollutant and toxins are substances
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3 years ago
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The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab. How many moles of dextrose is this equivalent t
Katena32 [7]

The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab the moles of dextrose is this equivalent to is 3.6888 moles.

<h3>What are moles?</h3>

A mole is described as 6.02214076 × 1023 of a few chemical unit, be it atoms, molecules, ions, or others. The mole is a handy unit to apply due to the tremendous variety of atoms, molecules, or others in any substance.

To calculate molar equivalents for every reagent, divide the moles of that reagent through the moles of the restricting reagent. The calculation is follows:

  • 655/12 x 6 + 12+ 16 x 6
  • = 655/ 180 = 3.6888 moles.

Read more about moles:

brainly.com/question/24322641

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6 0
1 year ago
The vapor pressure of water at 25.0°C is 23.8 torr. Determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
mrs_skeptik [129]

According to Raoult's law the relative lowering of vapour pressure of a solution made by dissolving non volatile solute is equal to the mole fraction of the non volatile solute dissolved.

the relative lowering of vapour pressure is the ratio of lowering of vapour pressure and vapour pressure of pure solvent

\frac{p^{0-}p}{p^{0}}=x_{B}

Where

xB = mole fraction of solute=?

p^{0}=23.8torr

p = 22.8 torr

x_{B}=\frac{23.8-22.8}{23.8}=0.042

mole fraction is ratio of moles of solute and total moles of solute and solvent

moles of solvent = mass / molar mass = 500 /18 = 27.78 moles

putting the values

molefraction=\frac{molessolute}{molesolute+molessolvent}

0.042=\frac{molessolute}{27.78+molessolute}

1.167+0.042(molesolute)=molessolute

molessolute=1.218

mass of glucose = moles X molar mass = 1.218 X 180 = 219.24 grams



3 0
3 years ago
Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570
Andrews [41]

x = 1.01

Explanation:

Given equation:

   y = 1.2345x – 0.6789

   y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

  Since we have been given y = 0.570

        y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

     since  y = 0.570

     0.57 = 1.2345x – 0.6789

    add 0.6789 to both sides;

 0.57 + 0.6789 =  1.2345x – 0.6789 + 0.6789

  1.2489‬ =   1.2345x

Divide both sides by  1.2345

 \frac{1.2489}{  1.2345} = \frac{  1.2345x }{ 1.2345}

    x = 1.01

learn more:

Equations brainly.com/question/9045597

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7 0
3 years ago
Inside a room, the air is often warmer near the ceiling then near the floor. Which of the following accounts for this difference
Vanyuwa [196]
The correct answer is C. convection
4 0
2 years ago
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