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kupik [55]
3 years ago
11

In the laboratory you dilute 5.32 mL of a concentrated 6.00 M perchloric acid solution to a total volume of 100 mL. What is the

concentration of the dilute solution
Chemistry
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

0.3192 M

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5.32 mL Molarity of stock solution (M1) = 6 M

Volume of diluted solution (V2) = 100 mL

Molarity of diluted solution (M2) =?

We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:

M1V1 = M2V2

6 × 5.32 = M2 ×100

31.92 = M2 × 100

Divide both side by 100

M2 = 31.92 / 100

M2 = 0.3192 M

Therefore, the molarity of the diluted solution is 0.3192 M.

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Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

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6 0
1 year ago
Indicate the charge carried by the following atomic particles:
Dovator [93]
Answer:
A. Protons are positive and carry a charge of +1
B. Neutrons are neutral so carry a charge of 0
C. Electrons are negative and carry a charge of -1
5 0
2 years ago
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Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. The volume of gas collected is
Leya [2.2K]

The mass of oxygen collected from the thermal decomposition of potassium chlorate at a temperature of 297 K and 762 mmHg is 0.16 g

<h3>How to determine the mole of oxygen produced </h3>

We'll begin by obtaining the number of mole of oxygen gas produced from the reaction. This can be obtained by using the ideal gas equation as illustrated below:

  • Volume (V) = 0.128 L
  • Temperature (T) = 297 K
  • Pressure (P) = 762 – 22.4 = 739.6 mmHg
  • Gas constant (R) = 62.363 mmHg.L/Kmol
  • Number of mole (n) =?

PV = nRT

739.6 × 0.128 = n × 62.363 × 297

Divide both sides by 62.363 × 297

n = (739.6 × 0.128) / (62.363 × 297)

n = 0.0051 mole

Thus, the number of mole of oxygen gas produced is 0.0051 mole

<h3>How to determine the mass of oxygen collected</h3>

Haven obtain the number of mole of oxygen gas produced, we can determine the mass of the oxygen produced as follow:'

  • Mole = 0.0051 mole
  • Molar mass of oxygen gas = 32 g/mole
  • Mass of oxygen =?

Mole = mass / molar mass

0.0051 = mass of oxygen / 32

Cross multiply

Mass of oxygen = 0.0051 × 32

Mass of oxygen = 0.16 g

Thus, we can conclude that the mass of oxygen gas collected is 0.16 g

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1 year ago
At a temperature of 500 kelvins, 6 liters of an ideal gas had a pressure of 300 newtons
mr Goodwill [35]

Answer A

Explanation:

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it opposes motion. the object would continue to slide forever if not stopped by another object.

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