Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.
<span>160 Joules
For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance:
80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.
So the cart has a final kinetic energy of 160 Joules.</span>
The equivalent of the Newton's second law for rotational motions is:
where
is the net torque acting on the object
is its moment of inertia
is the angular acceleration of the object.
Re-arranging the formula, we get
and since we know the net torque acting on the (vase+potter's wheel) system,
, and its angular acceleration,
, we can calculate the moment of inertia of the system:
Answer: decreases.
direct.
Explanation:
when you have two objects which are far apart from each other, when the distance increases the forces of attraction decreases and vice versa when the distance decreases the forces of attraction also increases.
this is a direct relationship, from careful observation and monitoring of the simulation, a pattern is noticeable by which an increase in one variable causes an opposite effect on the other variable.
Answer:
hello the answer is 47m/s
