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2 years ago

IS THIS ANGLE ACUTE, RIGHT, OBTUSE , OR STRAIGHT?

Mathematics

1 answer:

oksian1 [2.3K]2 years ago

8 0

Answer: Obtuse

Step-by-step explanation:

Acute angles are Between 0 and 90 degrees

Right angles are 90 degrees

Obtuse angles are 90-180 degrees

And straight angles are 180 degrees

Note: Between mean like Ex. between 1-10 it would be 2, 3, 4,... 8, 9

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HELP ASAP WILL GIVE 100 POINTS. Solve for x. 89(54x−36)+2=−34(−40+16x)+90x

PolarNik [594]

Solution:

Simplify the equation and solve.

89(54x − 36) + 2 = −34(−40 + 16x) + 90x
=> 4806x − 3204 + 2 = 1360 - 544x + 90x
=> 4806x = 1360 - 454x + 3202
=> 5260x = 4562
=> x = 4562/5260 = 2281/2630

The solution to the problem is 2281/2630.

3 0

2 years ago

Help me answer for 11 points

Tcecarenko [31]

Answer:

Just Transposition...

Step-by-step explanation:

12×7=84=d

92-49=43=e

28+57=85=f

96÷16=6=g

11×8=88=h

95+5-29=100-29=71=I

55-6+21=70=j

88+8÷4=96÷4=16=k

19+24-97=-97-43=54=m

-20+17+61=61+3=64=n

hope it helps

4 0

2 years ago

Need help due today will give brainiest and the first of a string of questions just like this one PLZ SHOW WORK NEEDED TO TURN I

sleet_krkn [62]

Answer:

Sorry bro you are going to get it

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2 years ago

Find the inequality represented by the graph.

anzhelika [568]

Answer:

Step-by-step explanation:

y intercept is 3

y - 4 = 3 ( x - 4)

y - 4 = 3x - 12

y < 3x - 8

not equal to because the line is dashed.

not greater than because the shading is below the line

7 0

2 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

2 years ago