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victus00 [196]
2 years ago
13

2. What effect does temperature have on the strength of a magnet?

Chemistry
1 answer:
DIA [1.3K]2 years ago
4 0

Answer:

The more the temperature the less the effect if magnet

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Which of these is a pure substance
Galina-37 [17]

Both A and B are the answer.


4 0
3 years ago
A solid is crushed into a powder is chimacal change or pysical change
SSSSS [86.1K]

Answer:

Physical Change

Explanation:

A solid being crushed into a powder is a physical change because a chemical change is when substances combine to create new substances.

Hope this helps :)

4 0
3 years ago
What is spectrophotometry? How can this be useful in identifying drugs?
liq [111]

Answer:

What is spectrophotometry? It is an analytic method that it use substances light absorbance property

How can this be useful in identifying drugs? It possible compare spectra and identify problem substance

Explanation:

The way substances absorb light is unique and because of that it is possible to use spectrophotometry for substances identifying. the model spectra are measured in ideal conditions, so, it is difficult ensure the same conditions and to achieve identical spectra.

I hope I have been helpful

7 0
3 years ago
George was curious about the best way to recycle aluminum. His science teacher told him that there have been numerous studies al
solniwko [45]
I think that the answer is a research bc it’s just sounds like that right answer
3 0
3 years ago
Read 2 more answers
Strotium−90, a radioactive isotope, is a major product of an atomic bomb explosion. It has a half-life of 28.1 yr. (a) Calculate
Bess [88]

Answer :

(a) The first-order rate constant for the nuclear decay is, 0.0247\text{ years}^{-1}

(b) The fraction of 90-Sr that remains after 10 half-lives is, \frac{a_o}{1024}

(c) The time passed in years is, 127.4 years.

Explanation :

<u>Part (a) :</u>

Half-life = 28.1 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{28.1\text{ years}}

k=0.0247\text{ years}^{-1}

Thus, the first-order rate constant for the nuclear decay is, 0.0247\text{ years}^{-1}

<u>Part (b) :</u>

Now we have to calculate the fraction of 90-Sr that remains after 10 half-lives.

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives

a_o = Initial amount of the reactant

n = number of half lives  = 10

Now put all the given values in the above formula, we get:

a=\frac{a_o}{2^{10}}

a=\frac{a_o}{1024}

Thus, the fraction of 90-Sr that remains after 10 half-lives is, \frac{a_o}{1024}

<u>Part (c) :</u>

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.0247\text{ years}^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = 100 - 95.7 = 4.3

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0247}\log\frac{100}{4.3}

t=127.4\text{ years}

Therefore, the time passed in years is, 127.4 years.

6 0
3 years ago
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