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jolli1 [7]
4 years ago
5

What is the magnetic field inside a coil with the following conditions: 228 number of turns, 0.952 A of current and a length of

2.29 cms.
Physics
1 answer:
sdas [7]4 years ago
8 0

Answer:

The magnetic field inside a coil is 0.0119 T.

Explanation:

Given that,

Number of turns = 228

Current = 0.952 A

Length = 2.29 cm

We need to calculate the magnetic field

Using formula of magnetic field

B=\dfrac{\mu_{0}NI}{l}

Where, B = magnetic field

l = length

I = current

N = number of turns

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times228\times0.952}{2.29\times10^{-2}}

B=0.0119\ T

Hence, The magnetic field inside a coil is 0.0119 T.

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