The self-inductance of the solenoid is 8.25 mH.
The given parameters;
- <em>number of turns, N = 1700 turn</em>
- <em>length of the solenoid, l = 55 cm = 0.55 m</em>
- <em>diameter of solenoid, d = 4 cm</em>
- <em>radius of the solenoid, r = 2 cm = 0.02 m</em>
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The area of the solenoid is calculated as follows;
The self-inductance of the solenoid is calculated as follows;
Thus, the self-inductance of the solenoid is 8.25 mH.
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In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
(1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
while the distance between the first and the fifth minima is
(2)
If we use the formula to rewrite
, eq.(2) becomes
Which we can solve to find a, the width of the slit:
Answer: Minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.
Explanation:
Velocity is only in horizontal direction at the top most point which is similar to the velocity in the horizontal direction at the time of launch.
Now, according to the law of conservation of energy the formula used is as follows.
As speed at which the person is travelling was 6.8 m/s. Hence, the initial velocity will be calculated as follows.
Thus, we can conclude that minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.
Answer:
Are very small.
Explanation:
Scientists use models to study atoms because atoms are extremely small and can't even be seen.
Answer:
261.307 m
Explanation:
b = Base of triangle = 450 m
p = Perpendicular of the triangle
= Angle of the triangle =
From trigonometry
Height of the building = 1.5+259.807 = 261.307 m